Question

Please help me I would really appreciate it.

Answer 1

Given:

$\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}$

To prove:

$\Delta CDA\cong \Delta ABC$

Proof:

In $\Delta CDA\text{ and } \Delta ABC$,

$\overline{AB}\cong \overline {CD}$ because Given

$\overline{BC}\cong \overline {DA}$ because Given

$\overline{AC}\cong \overline {AC}$ because Reflexive property.

Corresponding sides of both triangles are congruent. So,

$\Delta CDA\cong \Delta ABC$ because SSS

Therefore, the required missing values are: Given, $\overline{BC}\cong \overline {DA}$, Reflexive property ,$\Delta CDA\cong \Delta ABC$, SSS respectively.