Let the angles be A and C
<span>Complimentary angles, therefor </span>
<span>A + C = 90 </span>
<span>The measurement of the complement of an angle exceeds the measure of the angle by 25% (you used a % sign so I'll use % instead of degrees) </span>
<span>C = 1.25A </span>
<span>Substitute </span>
<span>A + 1.25A = 90 </span>
<span>2.25A = 90 </span>
<span>A = 40º <----- </span>
<span>C = 50º <----- </span>
<span>------------------------------ </span>
<span>If you meant 25º </span>
<span>A + (A + 25) = 90 </span>
<span>2A + 25 = 90 </span>
<span>2A = 65 </span>
<span>A = 32.5º </span>
<span>C = 57.5º</span>
For the first digit, we have 5 options that are 4,5,6,7,8 . For the second digit, we have 4 options which are 3,4,5 or 6 and for the third digit, we have the options of all numbers except 2 or 5 that is 1,3,4,6,7,8,9,0 . SO we have 8 options for third digit . So to find the total number of options, we need to multiply all the possible options for each digit that is 5 times 4 times 8 = 160 . So the number of possible options are 160 .
50/100
5/10
hope that helped :)
Answer:
Step-by-step explanation:
4t + 11 = 19
Subtract 11 from both sides
4t = 19 - 11
4t = 8
Divide both sides by 4
t = 8/4
t = 2
Answer:
3003 different groups of 6tops
Step-by-step explanation:
Using the combination formula, generally, when selecting r number of objects out of a pool of n numbers, this can be done in nCr number of ways.
nCr = n!/(n-r)!r!
If there are 14 tops I'd like to purchase and I can only afford six, the number of ways I can choose this six at random from the 14tops can be done in 14C6 number of ways.
14C6 = 14!/(14-6)!6!
14C6 = 14!/8!6!
14C6 = 14×13×12×11×10×9×8!/8!×6×5×4×3×2
14C6 = 14×13×12×11×10×9/6×5×4×3×2
14C6 = 14×13×12×11/8
14C6 = 3003ways
