You can set up a system of equations for this problem. x= number of coach tickets and y = number of first class tickets.
$210x + $1200y = $10,230 (cost of coach ticket plus cost of first class tickets is total budget)
x + y = 11 (number of coach tickets plus number of first class tickets is total number of people)
Solve the second equation for y to get y = 11 - x, then plug that into the first equation and solve for x:
$210x + $1200(11 - x) = $10,230
$210x + $13,200 - $1200x = $10,230
-$990x + $13,200 = $10,230
-$990x = $2,970
x = 3
Sarah bought x = 3 coach tickets. Plug that into the second equation and solve for y:
3 + y = 11
y = 8
Sarah bought y = 8 first class tickets.
Answer:
the number to the right of the 7
Step-by-step explanation:
Answer:
Step-by-step explanation: so, he earns 5 dollars every day, and he starts off with 0 with the y=mx+b form you would y or m in this case is equal to 5x or is this case d so ot would be m=5d
Yes, I can solve that inequality.
Any value of ' r ' that's less than 1/3 is a solution.
Step-by-step explanation:
(square)+(rhombus)..............
