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lapo4ka [179]
3 years ago
5

What is the fifth term of (2x + y)^8?

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

Answer:

Expansion for there will be 9 terms.

(a+b) ^n =nco a^n b^o+ nc1 a^(n-1) b^1+nc2 a^(n-2) b^2+nc3 a(n-3) b^3+nc4  a^(n-4) b^4+...........................ncn a^o b^n.

5th term of  (2x+y)^8 = ?  

5th term is nC4 a^(n-4) b^4

a=2x, b=y, n=8

therefore 8C4 (2x)^(8-4)  (y)^4

8!/((8-4)! 4!) (2x)^4 y^4

40320/576  (16 x^4 ) (y^4)

70 (16x^4)(y^4)

1120 X^4 Y^4

Step-by-step explanation:

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Tran is solving the quadratic equation 2x2 – 4x – 3 = 0 by completing the square. His first four steps are shown in the table.
natulia [17]

The solution to the quadratic equation 2x² - 4x - 3 = 0 is x = 1 ± √2.5

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Solving the polynomial using completing the square:

2x² - 4x - 3 = 0

First divide through by 2:

x² - 2x - 3/2 = 0

add 3/2 to both sides:

x² - 2x - 3/2 + 3/2 = 0 + 3/2

x² - 2x = 3/2

add the square of half the coefficient x to both sides:

x² - 2x + 1 = 3/2 + 1

(x - 1)² = 2.5

taking square root:

x - 1 = ±√2.5

x = 1 ± √2.5

The solution to the quadratic equation 2x² - 4x - 3 = 0 is x = 1 ± √2.5

Find out more on equation at: brainly.com/question/2972832

#SPJ1

7 0
1 year ago
Surface area of the prism
Rudik [331]

Answer: You basically have to 2xlw+2wh+2lh which means

2 multiplied by the length and width + 2 x the width and the height+ 2 x the length and height

Example:

l= 2

w=5

h=4

2x2x5+2x5x4+2x2x4

I hope this helps

5 0
3 years ago
-5x + 12 - 7x = -3(5x + 8)
nikitadnepr [17]

Simplify -5x + 12 - 7x to -12x + 12

-12x + 12 = -3(5x + 8)

Expand

-12x + 12 = -15x - 24

Add 15x to both sides

-12x + 12 + 15x = -24

Simplify 12x + 12 + 15x to 3x + 12

3x + 12 = -24

Subtract 12 from both sides

3x = -24 - 12

Simplify -24 - 12 to -36

3x = -36

Divide both sides by 3

x = -36/3

Simplify 36/3 to 12

<u>x = -12</u>

7 0
3 years ago
35 Points!!
nexus9112 [7]

Answer:

- Equal midpoints of AC and BC.

- The product of the slopes of the diagonals AC and DB is -1.

Step-by-step explanation:

1. Plot the given points, as you can see in the graph attached.

2. Calculate the midpoint of AC and DB:

M_{AC}=(\frac{-5+(-1)}{2},\frac{-1+5}{2})=(-3,2)\\M_{DB}=(\frac{-9+3}{2},\frac{6+(-2)}{2})=(-3,2)

Therefore, the midpoint of AC and DB are equal.

3. Calculte the slope of the diagonals AC and DB:

m_{AC}=\frac{5-(-1)}{-1-(-5)}=\frac{3}{2}\\m_{DB}=\frac{-2-6)}{3-(-9)}=-\frac{2}{3}

4. Multiply the slopes of the diagonals:

(\frac{3}{2})(-\frac{2}{3})=-1 (AC and DB are perpendicular)

5 0
3 years ago
Solve 5^5x=(125)^x+2
miv72 [106K]

Answer:

x = 3

Step-by-step explanation:

5^5x = (5³)^x+2

5^5x = 5^3x+6

5x = 3x + 6

2x = 6

x = 3

5 0
2 years ago
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