2 years ago

What is the fifth term of (2x + y)^8?

Mathematics

1 answer:

astra-53 [7]2 years ago

8 0

Answer:

Expansion for there will be 9 terms.

(a+b) ^n =nco a^n b^o+ nc1 a^(n-1) b^1+nc2 a^(n-2) b^2+nc3 a(n-3) b^3+nc4 a^(n-4) b^4+...........................ncn a^o b^n.

5th term of (2x+y)^8 = ?

5th term is nC4 a^(n-4) b^4

a=2x, b=y, n=8

therefore 8C4 (2x)^(8-4) (y)^4

8!/((8-4)! 4!) (2x)^4 y^4

40320/576 (16 x^4 ) (y^4)

70 (16x^4)(y^4)

1120 X^4 Y^4

Step-by-step explanation:

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