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lana [24]
3 years ago
13

Simplify: |(–3.86 + 6.82)| + |(4.02 – 12.45)|

Mathematics
1 answer:
Lana71 [14]3 years ago
4 0

600dot82 - 1229

———————--

100

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________ is the process of associating numerical amounts to the reported in financial statements.
Len [333]

Answer:

Measurement

Step-by-step explanation:

In accounting and finance, measurement is when you assign, through computation, a numerical amount, be it money, hours, or other units to a piece of data. In accounting, measurement usually associates the mayority of the data represented in terms of money.

7 0
4 years ago
I absolutely suck in math so please just help me
agasfer [191]

All you have to do is substitute the values of x.

h(0) = |-3(0) + 5|

h(0) = |5|

h(0) = 5

The answer for h(0) is 5.

h(5) = |-3(5) +5|

h(5) = |-15 + 5|

h(5) = |-10|

h(5) = 10

The answer to h(5) is 10.

I hope this helps!

5 0
3 years ago
Find the distance between each pair of points. Round your answer to the nearest tenth, if necessary. Hint: Use the Pythagorean T
Paul [167]

The distance between two points on the plane is given by the formula below

\begin{gathered} A=(x_1,y_1),B=(x_2,y_2) \\ \Rightarrow d(A,B)=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2} \end{gathered}

Therefore, in our case,

A=(-1,-3),B=(5,2)

Thus,

\begin{gathered} \Rightarrow d(A,B)=\sqrt[]{(-1-5)^2+(-3-2)^2}=\sqrt[]{6^2+5^2}=\sqrt[]{36+25}=\sqrt[]{61} \\ \Rightarrow d(A,B)=\sqrt[]{61} \end{gathered}

Therefore, the answer is sqrt(61)

In general,

-(-n)=n

Remember that

-n=(-1)\cdot n

Therefore,

\begin{gathered} a-(-n)=a+(-1)(-n)=a+(-1)(-1\cdot n)=a+(-1)^2\cdot n=a+1\cdot n=a+n \\ \Rightarrow a-(-n)=a+n \end{gathered}

6 0
1 year ago
Take away 6 from 5 times g ~ in albebraic expression.
Brrunno [24]

5g-6 when you multiply a verable with a number you simplily put the letter beside the number and that lets us know to multiply:)
4 0
3 years ago
Choose any positive integer. Powers of two here are not very interesting, so choose something else. If the number you have chose
Yakvenalex [24]

Answer:

Step-by-step explanation:

Let the integer be 6 for even and 7 for odd (say)

For 6, we divide by 2, now get 3.  Now we multiply by 3 and add 1 to get 10. Now since 10 is even divide by 5, now multiply by 3 and add 1 to get 16.  Now divide by 2 again by 2 again by 2 again by 2 till we get rid of even numbers.

The result is 1, so multiply by 3 and add 1 we get 4 now divide 2 times by 2 to get 1, thus this result now again repeats after 2 times.

Say if we select off number 3, multiply by 3 and add 1 to get 10 now divide by 5, now repeat the same process as above for 5 until we get 1 and it gets repeated every third time.

Thus whether odd or even after some processes, we get 1 and the process again and again returns to 1.

5 0
3 years ago
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