Answer:
Explanation:
Given that,
Initially, the spaceship was at rest, u = 0
Final velocity of the spaceship, v = 11 m/s
Distance accelerated by the spaceship, d = 213 m
We need to find the acceleration experienced by the occupants of the spaceship during the launch. It is a concept based on the equation of kinematics. Using the third equation of motion to find acceleration.
So, the acceleration experienced by the occupants of the spaceship is .
Answer:
7.888m
Explanation:
Given:
frequency 'f'= 90Hz
velocity of the sound 'v' = 340 m /sec
The wavelength of the wave is given by,
λ= v/f => 340/90
λ= 3.777m
The destructive interference condition is givn by
Δd= λ
where, m=0,1,2,3,..
m=0, for minimum destructive interference
Δd= x 3.777
Δd=1.888
Therefore, the required distance is
=
+ Δd => 6 + 1.888
= 7.888m
Thus, So the speaker should be placed at 7.888 m
Answer:
Explanation:
At the point when light is vertically polarized is incident on the polarizer whose axes are situated at angle points the intensity power in the wake of going through all the polarisers is given by the Malus law, applied threefold for every one of the three axes.
The heading of the direction of the polarization is equivalent to the pivoted axes of the polarizer provided that light is an electromagnetic wave, its course of polarization is therefore controlled by the electric field part.
∴
a)
When sheet A is removed, the transmitted light goes through B, at 30°.
b)
When B is removed, No light passes since the axis of A and the axis of C are perpendicular to each other.
c)
When C is removed, the intensity is indeed zero since the axes are aligned and adjusted at 90° to one another.