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Keith_Richards [23]
3 years ago
15

A 60-W light bulb radiates electromagnetic waves uniformly in all directions. At a distance of 1.0 mfrom the bulb, the light int

ensity is I0, the average energy density of the waves is u0, and the rms electric and magnetic field values are E0 and B0, respectively.
At 2.0 m from the bulb, what is the light intensity?
Physics
1 answer:
yaroslaw [1]3 years ago
3 0

Answer:

I0/4

Explanation:

If the difference is increasedby a factor of two(i.e twice it's original value), then the light intensity happens to get reduced by one-fourth. This means that the light intensity would be:

I0/4

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Which interaction between x-ray photons and matter results in total absorption of the incident photon?
Leno4ka [110]

Answer:

Photoelectric effect        

Explanation:

In the photoelectric effect, when an x-ray strikes on a metal surface, the energy is completely absorbed by the metal. If the energy would be equal to or more than work function of  metal, electron ejects out. The kinetic energy of the electron which is ejected depends on the energy of the incident radiation and work function of the metal.

4 0
4 years ago
Suppose the acceleration of an elevator is 1/2 g upward, then what is the reading on the scale in the elevator.
Irina-Kira [14]

Answer:

c. 3/2 mg

Explanation:

Given that the acceleration of an elevator is 1/2 g upward.

The reading on the scale of the elevator is the net external force acting on the elevator.

Let the force F acting on the elevator as shown,

By using Newton's 2nd law, F_{net}=ma

where, F_{net} is the net force acting on the elevator.

m is the mass of the elevator,

a is the acceleration of the elevator, as given a=1/2 g upward.

So, F_{net}=m\times \frac 1 2 g

F-mg=m\times \frac 1 2 g \\\\F=mg+ \frac 1 2 mg \\\\F= \frac 3 2 mg.

So, the reading on the scale in the elevator is \frac 3 2 mg.

Hence, option (c) is correct.

4 0
3 years ago
Which of these most likely represents a chemical change? water boiling sugars digested by saliva mud drying to dirt ice cream me
mote1985 [20]
I think the correct answer would be <span> sugars digested by saliva. This describes a chemical change since new substances are produced since reaction happens due to the enzymes in the saliva. Hope this answers the question. Have a nice day.</span>
6 0
3 years ago
Read 2 more answers
What is friction and how does it affect objects in motion?
lesantik [10]
Friction is a force. A resistance force that tries to slow down and stop objects in motion. The difference between friction and air resistance is that friction acts on surfaces. For example, if I were skateboarding on a rough surface, more friction would occur so I would travel slower. If I were skareboarding on ice, I would go faster because there is much less friction to slow me down. Hope that helps:)
3 0
4 years ago
Read 2 more answers
You drop a single coffee filter of mass 1.5 grams from a very tall building, and it takes 49 seconds to reach the ground. In a s
Tresset [83]

(a) 0.0147 N

When the filter reaches the terminal speed, it means that its acceleration is now zero, so the net force acting on it is zero.

There are only two forces acting on the filter:

- The weight of the filter, downward: W = mg, where

m=1.5 g = 0.0015 kg is the mass of the filter

g=9.8 m/s^2 is the acceleration due to gravity

- The air resistance, upward, F_a

Since the net force is zero, we have

W-F_a =0

and solving the equation we find the upward force of air resistance:

F_a=W=mg=(0.0015kg)(9.8 m/s^2)=0.0147 N

(b) 0.0441 N

The problem is exactly identical to before, but this time the mass of the stack of filters is 3 times the mass of the single filter, so

m=3 (0.0015 kg)=0.0045 kg

And so, the upward force of air resistance is

F_a = mg=(0.0045 kg)(9.8 m/s^2)=0.0441 N

(c) 28.3 s

We know that the single coffee filter takes t=49 s to reach the ground, travelling at constant terminal speed of v, so the distance covered (the height of the building) is

d=vt

where t = 49 s.

We also know that the air resistance is proportional to the square of the terminal speed:

F_{air} \propto v^2

which means

v\propto \sqrt{F_{air}}

For the stack of three filters, we found (b) that the air resistance is 3 times the air resistance for the single filter (a). Therefore, the terminal speed of the stack of filter will be \sqrt{3} times larger than the terminal speed of the single filter.

Therefore, the time taken will be:

t'=\frac{d}{v'}=\frac{d}{\sqrt{3} v}=\frac{t}{\sqrt{3}}

And since t = 49 s, we have

t'=\frac{49 s}{\sqrt{3}}=28.3 s

8 0
3 years ago
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