A.5 kg model rocket launches with a thrust of 5 n in the upward direction. can it lift off of the ground? (hint: gravity is pull
1 answer:
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Answers:
A)
B) 22. 5 N
Explanation:
A) Since this situation is related to uniform circular motion, the centripetal acceleration of the child is calculated by:
Where:
is the speed
is the child's distane to the center (the radius)
Hence:
B) Knowing th centripetal acceleration and the mass of the child, we can calculate the net horizontal force
by:
Answer:
The relative velocity of the motorcycle to a passenger in the car is 30 km/h
Explanation:
The question relates to the principle of relative velocity and reference frames
The given parameters are;
The velocity of the motorcycle, v₁ = 120 km/h
The velocity of the car, v₂ = 90 km/h
The relative velocity of an object X with regards to another object Y is the velocity the object X will seem to be moving with to an observer in the rest frame of object Y written as =
-
Therefore, the relative velocity of the motorcycle to the car is = v₁ - v₂, which give;
= 120 km/h - 90 km/h = 30 km/h
The relative velocity of the motorcycle to a passenger in the car = 30 km/h.