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Rashid [163]
4 years ago
13

After the Collision the two car stick together find the final velocity of the two cars​

Physics
1 answer:
adelina 88 [10]4 years ago
8 0

Answer:

The two blocks collide in a totally inelastic collision (That means they stick together after they collide). What is their common final velocity after the inelastic collision? ... So we will find the total momentum initially, before the collision, and set that equal to the ... Example: Two cars collide at an intersection as sketched below.

Explanation:

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How long must a pendulum be to have a period of 4.6 5 on Neptune, where g = 11.15 m/s?​
Anon25 [30]

Answer:

5.98 m

Explanation:

T=2\pi \sqrt\frac{L}{g}

T^2=4\pi ^2L/g\\L = gT^2/(4\pi^2) = 11.15*4.6²/(4π²) = 5.98 m

5 0
2 years ago
A train starts from a station with a constant acceleration of at = 0.40 m/s2. A passenger arrives at the track time t = 6.0s aft
jok3333 [9.3K]

Answer:

4.8 m/s  

Explanation:

When she catches the train,

  1. They will have travelled the same distance.and
  2. Their speeds will be equal

The formula for the distance covered by the train  is

d = ½at² = ½ × 0.40t² = 0.20t²

The passenger starts running at a constant speed 6 s later, so her formula is

d = v(t - 6.0)

The passenger and the train will have covered the same distance when she has caught it, so

(1) 0.20t² = v(t - 6.0)

The speed of the train is

v = at = 0.40t

The speed of the passenger is v.

(2) 0.40t = v

Substitute (2) into (1)

0.20t² = 0.40t(t - 6.0) = 0.40t² - 2.4 t

Subtract 0.20t² from each side

0.20t² - 2.4t = 0

Factor the quadratic

t(0.20t - 2.4) = 0

Apply the zero-product rule

t =0     0.20t - 2.4 = 0

                   0.20t = 2.4

(3)                      t = 12

We reject t = 0 s.

Substitute (3) into (2)

0.40 × 12 = v

            v = 4.8 m/s

The slowest constant speed at which she can run and catch the train is 4.8 m/s.

A plot of distance vs time shows that she will catch the train 6 s after starting. Both she and the train will have travelled 28.8 m. Her average speed is 28.8 m/6 s = 4.8 m/s.

7 0
4 years ago
A Chinook salmon can jump out of water with a speed of 6.70 m/s6.70 m/s . How far horizontally dd can a Chinook salmon travel th
aksik [14]

Answer:

R = 3.88 m

Explanation:

As the Chinook salmon leaves the water till it gets back into the water it is performing a projectile motion with the following parameters:

V₀ = Launch Speed = 6.7 m/s

θ = Launch Angle = 29°

R= Range of Projectile= Horizontal Distance Covered by Chinook salmon= ?

The value of the range of a projectile is given by the following formula:

R = (V₀² Sin 2θ)/g

R = [(6.7 m/s)² Sin {(2)(29°)}/(9.8 m/s²)]

R = [(6.7 m/s)² Sin (58°)/(9.8 m/s²)]

<u>R = 3.88 m</u>

8 0
4 years ago
During a baseball game, a baseball is struck at ground level by a batter. The ball leaves the baseball bat with an initial speed
krok68 [10]

Answer:

Detailed solution is given below:

3 0
3 years ago
In about 5 billion years, at the end of its lifetime, our sun will end up as a white dwarf, having about the same mass as it doe
masya89 [10]
The formula of density is given by

Density = Mass ÷ Volume

We have:
Mass = 1.989 × 10³⁰ kg
Volume = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (7500)^3 = 1.767*10^12 km³

Density = \frac{(1.989)(10^{30})}{(1.767)(10^{12})}=1.13×10¹⁸ kg/km³

Converting 1.13 × 10¹⁸ kg/km³ to g/cm³

1.13 × 10¹⁸ kg = 1.13 × 10¹⁸ × 10³ = 1.13 × 10²¹ grams
1 km³ = 1 × 10⁶ cm³ 

(1.13 × 10²¹) ÷ 10⁶ = 1.13 × 10¹⁵ gr/cm³

Answer: Density 1.13 × 10¹⁵ gr/cm³
8 0
4 years ago
Read 2 more answers
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