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3 years ago

Problem 10: A simple pendulum with mass, m=1 kg and length, L=2.0 m is released by

Physics

1 answer:

vova2212 [387]3 years ago

3 0

Answer:

A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?

Explanation:

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2. You and a friend are spending a weekend at a carnival. You get bored and begin to make electrostatics measurements. It turns

aleksklad [387]

Answer:

B) -2 Coulombs

Explanation:

In order to find the net charge, we must add the charge that you have with the charge that your friend has, but taking into account the different sign. In fact, we have:

- Charge possessed by you: Q1 = +3 C

- Charge possessed by your friend: Q2 = -5 C

Therefore, the net charge possessed by both persons will be given by

Q = Q1 + Q2 = +3 C + (-5 C) = +3 C - 5 C = -2 C

8 0

3 years ago

Work of 2 joules is done in stretching a spring from its natural length to 11 cm beyond its natural length. what is the force (i

Sidana [21]

The law applied here is Hooke's Law which describes the force exerted by the spring with a given distance. The equation for this is F = kΔx, where F is the force in Newtons, k is the spring constant in N/m while Δx is the displacement in meters.

If you want to find work done by a spring, this can be solved by using differential equations. However, derived equations are already ready for use. The equation is

W = k[{x₂-x₁)² - (x₁-xn)²],

where
xn is the natural length
x₁ is the stretched length
x₂ is also the stretched length when stretched even further than x₁

In this case xn =x₁. So, that means that (x₁-xn) = 0 and (x₂-x₁) = 11 cm or 0.11 m.

Then, substituting the values,

2 J = k (0.11² -0²)
k = 165.29 N/m

Finally, we use the value of k to the Hooke's Law to determine the Force.

F = kΔx = (165.29 N/m)(0.11 m)
F = 18.18 Newtons

5 0

4 years ago

Darna rolls the 7.05-kg ball down the lane and it hits the 1.52-kg pin head on. The ball was moving at 8.24 m/s before the colli

Amiraneli [1.4K]

Answer:

The velocity of the ball after the collision is 5.39 m/s

Explanation:

Hi there!

To solve this problem, we will use the conservation of momentum: the momentum of the system ball-pin remains the same before and after the collision. The momentum of the system is calculated as follows:

momentum before the collision (initial momentum) = mb · vb1 + mp · vp1

momentum after the collision (final momentum) = mb · vb2 + mp · vp2

Where:

mb = mass of the ball = 7.05 kg

vb1 = velocity of the ball before the collision = 8.24 m/s

mp = mass of the pin = 1.52 kg

vp1 = velocity of the pin before the collision = 0 m/s.

vb2 = velocity of the ball after the collsion = unknown.

vp2 = velocity of the pin after the collision = 13.2 m/s

Since momentum is conserved, then:

initial momentum = final momentum

mb · vb1 + mp · vp1 = mb · vb2 + mp · vp2

Solving for vb2:

mb · vb1 + mp · vp1 - mp · vp2 = mb · vb2

(mb · vb1 + mp · vp1 - mp · vp2) / mb = vb2

Since the pin is initially at rest, vp1 = 0:

(mb · vb1 - mp · vp2) / mb = vb2

(7.05 kg · 8.24 m/s - 1.52 kg · 13.2 m/s) / 7.05 kg = vb2

vb2 = 5.39 m/s

The velocity of the ball after the collision is 5.39 m/s

4 0

3 years ago

Does light have to have a medium to pass through?

skad [1K]

Answer:

Light does not require any medium to travel because light is a transverse wave

hope it helps

7 0

3 years ago

An object with a mass of 5.0 kg accelerates 8.0 m/s2 when an unknown force is applied to it. what is the amount of the force

BigorU [14]

The force is 40 newtons.
The formula for force is mass × acceleration = force. So in this case it would be 5 × 8 = 40.

4 0

4 years ago