Answer:
The value of capillary rise in the tube = 0.0363 cm
Explanation:
Diameter of the glass tube = 0.03 meter
Contact angle = 22 degree
We know that the capillary rise (h) in the tube is given by the formula =
h = (2 α cos β) / (d g R )
⇒ d = density of gasoline = 749 kg / 
β = 22 degree
R = radius of the tube = 0.015 m
α = surface tension of gasoline = 0.0216 N / m
cos 22 = 0.927
Put all the values in the above formula we get
⇒ h = (2 × 0.0216 × 0.927) / (749 × 9.81 × 0.015)
⇒ h = 0.0363 cm
This is the value of capillary rise in the tube.
Answer:
height from where rock was thrown is 27.916 m
Explanation:
speed = 7.50 m/s
θ = 30°
g= 9.8 m/s²
horizontal distance = 18 m
time require for vertical displacement
t = 2.8 sec
now for calculation of height
s = ut + 0.5 a t²
-h = v sinθ× t + 0.5 ×(-9.8)× (2.8²)
-h = 7.5 sin30°× 2.8 - 0.5 ×(9.8)× (2.8²)
-h = -27.916 m
h= 27.916 m
height from where rock was thrown is 27.916 m
Answer:
d=1.25 m
Explanation:
fd=.5mv2-.5mv1; 10(d)=.5(50)(.5)-0; 10(d)=12.5; d=12.5/10; d=1.25 m
Answer:
correct answer is iron
Explanation:
solution
as Iron is only formed in the cores of the star that is more massive than the sun because it takes very much energy as gravitational force push inward on the star
and the sun can form the helium and carbon and the oxygen and also other elements
but not the iron or any iron group element
so correct answer is iron
Answer:
its speed is insignificant before the diver's speed change, so the result does not change
Explanation:
In this exercise of conservation of the momentum, the system is formed by the diver and the Earth
initial instant (before jumping)
p₀ = 0
final instant (after jumping)
= m v + M v²
how momentum is conserved
p₀ = p_{f}
0 = m v + M v²
v² = m / M v
since the mass of the Earth is M = 10²⁴ kg
its speed is insignificant before the diver's speed change, so the result does not change
