3 years ago

What is the independent variable?

Physics

1 answer:

Marina86 [1]3 years ago

3 0

Answer:

a variable (often denoted by x ) whose variation does not depend on that of another.

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4. As a 500 N woman sits on the floor, the floor exerts a force on her of

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Its double her weight

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. Prior to Remy's trip to Cleveland, his uncle tells him about this amazing barbecue restaurant there and raves about

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A simple pendulum has a period of 3.45 second, when the length of the pendulum is shortened by 1.0m, the period is 2.81 second c

den301095 [7]

Answer:

Original length = 2.97 m

Explanation:

Let the original length of the pendulum be 'L' m

Given:

Acceleration due to gravity (g) = 9.8 m/s²

Original time period of the pendulum (T) = 3.45 s

Now, the length is shortened by 1.0 m. So, the new length is 1 m less than the original length.

New length of the pendulum is, $L_1=L-1$

New time period of the pendulum is, $T_1=2.81\ s$

We know that, the time period of a simple pendulum of length 'L' is given as:

$T=2\pi\sqrt{\frac{L}{g}}$ -------------- (1)

So, for the new length, the time period is given as:

$T_1=2\pi\sqrt{\frac{L_1}{g}}$ ------------ (2)

Squaring both the equations and then dividing them, we get:

$\dfrac{T^2}{T_1^2}=\dfrac{(2\pi)^2\frac{L}{g}}{(2\pi)^2\frac{L_1}{g}}\\\\\\\dfrac{T^2}{T_1^2}=\dfrac{L}{L_1}\\\\\\L=\dfrac{T^2}{T_1^2}\times L_1$

Now, plug in the given values and calculate 'L'. This gives,

$L=\frac{3.45^2}{2.81^2}\times (L-1)\\\\L=1.507L-1.507\\\\L-1.507L=-1.507\\\\-0.507L=-1.507\\\\L=\frac{-1.507}{-0.507}=2.97\ m$

Therefore, the original length of the simple pendulum is 2.97 m

4 0

3 years ago

Plzz Help easy quesion for 20 points Why does someone get burned if they touch an old filament bulb that has been on for a few h

fgiga [73]

Incandescent lights get hot very quickly and therefore can easily burn u or catch fire

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3 years ago

Read 2 more answers

If 0.5 A is flowing through a household light

stiks02 [169]

Answer:

60W

Explanation:

P=IV=0.5x120

P =60W

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3 years ago