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dem82 [27]
3 years ago
7

What is the difference between HTML and CSS? * 1. CSS is a markup language unlike HTML 2. HTML is a backend technology and CSS i

s a front end technology. 3. HTML focuses on a web page's structure and CSS focuses on its presentation 4. As of HTML5 there is no difference
Computers and Technology
1 answer:
grin007 [14]3 years ago
4 0

Answer: 3. HTML focuses on a web page's structure and CSS focuses on its presentation.

Explanation: HTML is designed to allow you to add the content and format it correctly. However, CSS's job is to allow for stylizing.

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What is the imitation of representing numbers with fixed point representation?
Tanzania [10]

Answer:

Hello your question is not complete, The complete question is ; <em>what is the Limitation of representing numbers with fixed point representation</em>

answer:  Limited range of values that can be represented

Explanation:

The limitation of representing numbers with fixed point representation is that there is a Limited range of values that can be represented using this method of representation

Fixed point  representation is a type of representation whereby there is a  fixed number of bits for both integer parts and fractional part.

4 0
2 years ago
A datagram network allows routers to drop packets whenever they need to. The probability of a router discarding a packetis p. Co
tresset_1 [31]

Answer:

a.) k² - 3k + 3

b.) 1/(1 - k)²

c.) k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

Explanation:

a.) A packet can make 1,2 or 3 hops

probability of 1 hop = k  ...(1)

probability of 2 hops = k(1-k)  ...(2)

probability of 3 hops = (1-k)²...(3)

Average number of probabilities = (1 x prob. of 1 hop) + (2 x prob. of 2 hops) + (3 x prob. of 3 hops)

                                                       = (1 × k) + (2 × k × (1 - k)) + (3 × (1-k)²)

                                                       = k + 2k - 2k² + 3(1 + k² - 2k)

∴mean number of hops                = k² - 3k + 3

b.) from (a) above, the mean number of hops when transmitting a packet is k² - 3k + 3

if k = 0 then number of hops is 3

if k = 1 then number of hops is (1 - 3 + 3) = 1

multiple transmissions can be needed if K is between 0 and 1

The probability of successful transmissions through the entire path is (1 - k)²

for one transmission, the probility of success is (1 - k)²

for two transmissions, the probility of success is 2(1 - k)²(1 - (1-k)²)

for three transmissions, the probility of success is 3(1 - k)²(1 - (1-k)²)² and so on

∴ for transmitting a single packet, it makes:

     ∞                             n-1

T = ∑ n(1 - k)²(1 - (1 - k)²)

    n-1

   = 1/(1 - k)²

c.) Mean number of required packet = ( mean number of hops when transmitting a packet × mean number of transmissions by a packet)

from (a) above, mean number of hops when transmitting a packet =  k² - 3k + 3

from (b) above, mean number of transmissions by a packet = 1/(1 - k)²

substituting: mean number of required packet =  k^{2}  - 3k + 3 * \frac{1}{(1 - k)^{2} }\\\\= \frac{k^{2} - 3k + 3 }{(1-k)^{2} }

6 0
3 years ago
Julie: 3: 36, 6:72, 9:108....tell me the next 3 ratios * math*
svlad2 [7]

Answer:

12:144, 15:180,

Explanation:

8 0
3 years ago
While the economy of eastern Washington relies on farming, western Washington relies on technology.
Strike441 [17]
True- western Washington hosts modern technologies supporting both academic and co curricular activities
3 0
3 years ago
Read 2 more answers
If you type too much text on a PowerPoint slide the additional text is _____
IrinaK [193]
The text just goes out of the slide and you can't see it until you lower the font size or until you delete some of it.
3 0
3 years ago
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