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ehidna [41]
3 years ago
5

F(x) =5x^2-20x+3 how to find minimum

Mathematics
1 answer:
Leya [2.2K]3 years ago
3 0

Answer:

(2,-17) should be the minimum.

Step-by-step explanation:

The minimum of a quadratic function occurs at x=-\frac{b}{2a} . If a is positive, the minimum value of the function is f(-\frac{b}{2a})

f_{min}x=ax^2+bx+c occurs at x=-\frac{b}{2a}

Find the value of x=-\frac{b}{2a}

x = 2

evaluate f(2).

replace the variable x with 2 in the expression.

f(2)=5(2)^2-20(2)+3

simplify the result.

f(2)=5(4)-20(2)+3

f(2)=20-40+3

f(2)=-17

The final answer is -17

Use the x and y values to find where the minimum occurs.

HOPE THIS HELPS!

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