Question

F(x) =5x^2-20x+3 how to find minimum

Answer 1

Answer:

(2,-17) should be the minimum.

Step-by-step explanation:

The minimum of a quadratic function occurs at $x=-\frac{b}{2a}$ . If a is positive, the minimum value of the function is $f(-\frac{b}{2a})$

$f_{min}x=ax^2+bx+c$ occurs at $x=-\frac{b}{2a}$

Find the value of $x=-\frac{b}{2a}$

x = 2

evaluate f(2).

replace the variable x with 2 in the expression.

$f(2)=5(2)^2-20(2)+3$

simplify the result.

$f(2)=5(4)-20(2)+3$

$f(2)=20-40+3$

$f(2)=-17$

The final answer is -17

Use the x and y values to find where the minimum occurs.

HOPE THIS HELPS!