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yanalaym [24]
3 years ago
6

A square flag includes three colors: yellow, black, and green. The colors of the flag appear in the proportion 3:2:1, with yello

w accounting for the greatest area and green accounting for the least. If a total of 48 square inches of the flag is black, what are the dimensions of the flag?
Mathematics
1 answer:
jeka57 [31]3 years ago
3 0

Answer:

423

Step-by-step explanation:

2313

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Alex Ar [27]
I’m guessing it’s the first one
4 0
3 years ago
6. The value of (tan 1° tan2º tan 3º ... tan 89°) is​
Thepotemich [5.8K]

Answer:

1

Step-by-step explanation:

Using the trigonometric identities

tan(90 - x) = cotx , cotx = \frac{1}{tanx}

Given

tan1tan2tan3....................... tan87tan88tan89

= tan1tan2tan3............... tan(90-3)tan(90-2)(tan90 - 1)

= tan1tan2tan3.............. cot3cot2cot1

= tan1cot1tan2cot2tan3cot3 ........................

= 1 × 1 × 1 ×....................... × 1

= 1

4 0
3 years ago
Help with this thing ??
serious [3.7K]

Answer:

1/4

Step-by-step explanation:

I'm not sure if he wants the Dilution factor or the scale but anyway

CBA = 4 C'B'A'

Scale 1/4

5 0
3 years ago
A bike shop rents bikes for $4.50 per hour, plus a $7.50 insurance charge. For how many hours can Peter rent a bike if he has $3
Mandarinka [93]

Answer:

With $30, Peter can afford 5 hours

Step-by-step explanation:

Given

Insurance Charge = $7.5

Charges = $4.5 per hour

Required

Determine the number of hours $30 can afford

First, we need to determine the equation.

<em>Total Charges = Charges per hour + Insurance Charge</em>

Substitute values for Charges per hour and Insurance Charge

Total Charges = 4.5 per hour + 7.5

Let the number of hours be n;

So,

Total Charges = 4.5n + 7.5

To calculate Peter's; substitute 30 for total charges

30 = 4.5n + 7.5

Subtract 7.5 from both sides

4.5n = 30 - 7.5

4.5n = 22.5

Divide both sides by 4.5

n = \frac{22.5}{4.5}

n = 5

Hence;

<em>With $30, Peter can afford 5 hours</em>

3 0
3 years ago
7 1/6 = 5 2/5 + p<br><br> p = ???
Crank

\huge\textbf{Hey there!}

\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}

\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}

\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}

\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}

\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}

\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}

\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}

\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}

\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}

\large\textsf{SIMPLIFY IT!}

\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}

\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark

\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}

~\frak{Amphitrite1040:)}

3 0
2 years ago
Read 2 more answers
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