Question

7 1/6 = 5 2/5 + p p = ???

Answer 1

Hope this helps ??!!

Answer 2

$\huge\textbf{Hey there!}$

$\mathbf{7\dfrac{1}{6} = 5\dfrac{2}{5} + p}$

$\rightarrow\mathbf{7 \dfrac{1}{6} = 5\dfrac{2}{5} + p}$

$\mathbf{\rightarrow p + 5\dfrac{2}{5}= 7\dfrac{1}{6}}$

$\mathbf{\rightarrow {p + \dfrac{27}{5}=\dfrac{43}{6}}}$

$\text{SUBTRACT }\rm{\dfrac{27}{5}}\text{ to BOTH SIDES}$

$\mathbf{p + \dfrac{27}{5} - \dfrac{27}{5} = \dfrac{43}{6}- \dfrac{27}{5}}$

$\text{CANCEL out: }\rm{\dfrac{27}{5} - \dfrac{27}{5}}\text{ because it gives you 0}$

$\text{KEEP: }\rm{\dfrac{43}{6} - \dfrac{27}{5}}\text{ because it help solve for the p-value}$

$\text{NEW EQUATION: }\rm{p = \dfrac{43}{6} - \dfrac{27}{5}}$

$\large\textsf{SIMPLIFY IT!}$

$\mathbf{p = \dfrac{53}{30} \approx p = 1\dfrac{23}{30}}$

$\huge\boxed{\textsf{Therefore, your answer is: \boxed{\mathsf{p = 1\dfrac{23}{30}}}}}\huge\checkmark$

$\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}$

~$\frak{Amphitrite1040:)}$