Answer:
The probability of selecting a family with exactly one male child is 1/4 or 0.25.
Step-by-step explanation:
Given in the question,
possible outcomes for the children's genders
{FFFF, FFFM, FFMF, FMFF, MFFF, MFFM, MFMF, MMFF, FFMM, FMFM, FMMF, FMMM, MFMM, MMFM, MMMF, MMMM}
= 16
To find,
the probability of selecting a family with exactly one male child
<h3>Probability = favourable outcomes / possible outcomes</h3>
favourable outcomes = {FFFM, FFMF, FMFF, MFFF}
= 4
Probability = 4 / 16
= 1 / 4
= 0.25
Answer:
0.8
Step-by-step explanation:
P(AP statistics) = 65%
P(AP Calculus) = 45%
P(AP statistics n AP Calculus) = 30%
Probability of AP statistics or AP Calculus but not both :
Probability of event A or B :
P(AUB) = p(A) + p(B) - p(AnB)
P(AP statistics U AP Calculus) = P(AP statistics) + P(AP Calculus) - P(AP statistics n AP Calculus)
= 0.65 + 0.45 - 0.30
= 0.8
= 80%
Answer:
sorryyyy i dont know the answer :-(
Step-by-step explanation:
sorryy
