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3 years ago

How many sides does a polygon have if the sum of the interior angles is 3420

Mathematics

2 answers:

ladessa [460]3 years ago

7 0

Answer:

i dont know

Step-by-step explanation:

yup

Dennis_Churaev [7]3 years ago

5 0

Answer: 21 sides

Step-by-step explanation: (n-2)=3420 you should divide each side by 180

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For 9-20 tell whether the first number is a multiple of the second number

jeyben [28]

Answer:

21,7 - yes

28,3 - no

17,3 - no

20,4 - yes

55,5 - yes

15,5 - yes

26,4 - no

32,8 - yes

48,7 no

60,2 - yes

79,4 - no

81,3 - yes

Step-by-step explanation:

hope that helps

7 0

3 years ago

After a big snow storm, Joe and Jim decided to shovel driveways for money. Jim shoveled 3 less than twice as many driveways as J

KIM [24]

Answer:

Joe shoveled 6, Jill shoveled 9

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

1. Here is a rule to make a list of numbers: Each number is the sum of the

boyakko [2]

Answer:

what the rest of the problem?

Step-by-step explanation:

8 0

3 years ago

Let f(x) = -2x - 7 and g(x) = -4x + 6. Find (fxg)(-5). a. -59 b. 3 c. 26 d. -6

DedPeter [7]

Answer:

Step-by-step explanation:

The given functions are:

$f(x) = - 2x - 7$

and

$g(x) = - 4x + 6$

$(f \times g)(x) = f(x) \times g(x)$

$(f \times g)(x) = ( - 2x - 7)( - 4x + 6)$

When we plug in x=-5, we get:

$(f \times g)( - 5) = ( - 4 \times - 5 + 6)( - 2 \times - 5 - 7)$

$(f \times g)( - 5) = ( 20 + 6)( 10 - 7)$

$(f \times g)(5) = ( 26)( 3) =7 8$

3 0

3 years ago

Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1, and the zeros 4 and 3−

Neko [114]

Answer:

$P(x) = x^3 - 10x^2+ 34x-40$

Step-by-step explanation:

Given

$p =1$ -- Leading coefficient

$Zeros: 4\ and\ 3 - i$

Required

Determine the polynomial

Represent the zeros with a and b

Such that

$a = 4$

$b = 3 - i$

The polynomial is:

$P(x) = p * (x - a) * (x - b)$

$P(x) = 1 * (x - 4) * (x - (3 - i))$

However, to solve further: We need to symmetrise over 3-i and its conjugate

$P(x) = 1 * (x - 4) * (x - (3 - i))* (x - (3 + i))$

$P(x) = (x - 4) * (x - (3 - i))* (x - (3 + i))\\\\$

To define a suitable function, the expression becomes

$P(x) = (x - 4) * ((x - 3)^2+1)$

$P(x) = (x - 4) * ((x - 3)(x - 3)+1)$

$P(x) = (x - 4) * (x^2 - 6x + 9+1)$

$P(x) = (x - 4) * (x^2 - 6x +10)$

Open bracket

$P(x) = x^3 - 6x^2 +10x - 4x^2 + 24x-40$

$P(x) = x^3 - 6x^2 - 4x^2+10x + 24x-40$

$P(x) = x^3 - 10x^2+ 34x-40$

5 0

3 years ago