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Gala2k [10]
3 years ago
12

Four more than three times a number is greater than 22

Mathematics
1 answer:
fenix001 [56]3 years ago
5 0

Answer:

4 + 3x > 22

More = Add +

Times a number = x

Greater Than = >

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im almost done with this hw. plz help!!! give explanation if you actually know the answer so ik u dont just want points
Vaselesa [24]

Answer:

he would have a 2/5 chance because he misses or hit three so he would either miss two or hit two according to the chart

Step-by-step explanation:

sry if I'm wrong but it would be one of the most valid answers

5 0
2 years ago
Read 2 more answers
Two groups of students were asked how many pets they had. The table below shows the numbers for each group:
Charra [1.4K]
Whats the question tho
6 0
3 years ago
Write the equation of the black line in slope-intercept form.
gavmur [86]
Y = x + 4
Slope = 1
Y-intercept = 4
7 0
2 years ago
Find b and s. At The present time Mrs. B's age is six years more than four times her sons age. Three years ago she was seven tim
padilas [110]

Answer:

Mrs. B's age = y = 38 years

her son's age = x = 8 years

Step-by-step explanation:

To Find:

Mrs. B's age = y =?

her son's age = x = ?

Solution:

Let Mrs. B's age  be 'y' years

and her son's age be 'x' years

Three years ago Mrs B's will be (y - 3) and her son's age will be (x - 3)

According to the first given condition,

y = 6 + 4x ...............Equation ( 1 )

According to the second given condition,

(y - 3 ) = 7 (x - 3 )..........Equation ( 2 )

equating equation 1 in equation 2 we get

6 + 4x -3 = 7x - 21

7x - 4x = 21 + 3

∴ 3x=24\\\therefore x =\frac{24}{3} \\\\\therefore x =8\ years

Now substitute x in equation 1 we get

y = 6 + 4×8

y = 6 + 32

∴ y = 38 years

Mrs. B's age = y = 38 years

her son's age = x = 8 years

6 0
2 years ago
) f) 1 + cot²a = cosec²a​
notsponge [240]

Answer:

It is an identity, proved below.

Step-by-step explanation:

I assume you want to prove the identity. There are several ways to prove the identity but here I will prove using one of method.

First, we have to know what cot and cosec are. They both are the reciprocal of sin (cosec) and tan (cot).

\displaystyle \large{\cot x=\frac{1}{\tan x}}\\\displaystyle \large{\csc x=\frac{1}{\sin x}}

csc is mostly written which is cosec, first we have to write in 1/tan and 1/sin form.

\displaystyle \large{1+(\frac{1}{\tan x})^2=(\frac{1}{\sin x})^2}\\\displaystyle \large{1+\frac{1}{\tan^2x}=\frac{1}{\sin^2x}}

Another identity is:

\displaystyle \large{\tan x=\frac{\sin x}{\cos x}}

Therefore:

\displaystyle \large{1+\frac{1}{(\frac{\sin x}{\cos x})^2}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{1}{\frac{\sin^2x}{\cos^2x}}=\frac{1}{\sin^2x}}\\\displaystyle \large{1+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}

Now this is easier to prove because of same denominator, next step is to multiply 1 by sin^2x with denominator and numerator.

\displaystyle \large{\frac{\sin^2x}{\sin^2x}+\frac{\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}}\\\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}

Another identity:

\displaystyle \large{\sin^2x+\cos^2x=1}

Therefore:

\displaystyle \large{\frac{\sin^2x+\cos^2x}{\sin^2x}=\frac{1}{\sin^2x}\longrightarrow \boxed{ \frac{1}{\sin^2x}={\frac{1}{\sin^2x}}}

Hence proved, this is proof by using identity helping to find the specific identity.

6 0
2 years ago
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