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3 years ago

Suppose BK is an angle bisector of △ABC. Find AB if BC=5, and AK=2.625, and KC=4.375.

Mathematics

2 answers:

12345 [234]3 years ago

5 0

Answer:

AB=3

Step-by-step explanation:

Given: AB=x, BC=5 AK=2.625, and KC=4.375

AB/BC=AK/KC

Because AK is similar to KC, and BA is similar to BC.

Triangle ABK and Triangle CBK are similar since they have an angle bisector.

so :

x/5=2.625/4.375

4.275x=2.625(5)

4.275x=13.125

x=13.125/4.275

x=3

AB=3

Zinaida [17]3 years ago

3 0

Answer:

AB = 3

Step-by-step explanation:

given that BK is an angle bisector then the following ratios are equal

$\frac{AB}{BC}$ = $\frac{AK}{KC}$

substitute relevant values into the equation and solve for AB

$\frac{AB}{5}$ = $\frac{2.625}{4.375}$ ( cross- multiply )

4.375AB = 13.125 ( divide both sides by 4.375 )

AB = 3

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3 years ago

The hypotenuse of a right triangle is 37 units long. Find the other two sides if the perimeter of the triangle is 84 units. Sepa

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Answer:

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Step-by-step explanation:

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