Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab, ![[ab]_K](https://tex.z-dn.net/?f=%20%5Bab%5D_K%20)
is equal to ![[ba]_K](https://tex.z-dn.net/?f=%20%5Bba%5D_K%20)
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus, ![[ab]_H = [ba]_H](https://tex.z-dn.net/?f=%20%5Bab%5D_H%20%3D%20%5Bba%5D_H%20)
. Since a and b were generic elements of H, then H/G is abelian.
Answer:
43.97
Step-by-step explanation:
just minus both the numbers but dont forget to put the percentage after the 55
Answer: n = -6
Step-by-step explanation:
3n+14=-4
Subtract 14 from both sides.
3n+14-14=-4-14
Simplify
3n=-18
Divide both sides by 3
3n/3 = -18/3
n=-6
Factor 11 x^2 y^2 out of both the numerator and the denominator to get 2(11 x^2 y^2)/11x^2 y^2, which is clearly equal to 2.
Answer:
This is true.
Congruent triangles have the same shape and the same size. So, you can position them so that one is superimposed (line up perfectly) on the other.
