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IceJOKER [234]
3 years ago
9

Def~=jkl and de =x^3-3x, kj=28,m

Mathematics
1 answer:
luda_lava [24]3 years ago
8 0
I need more information to answer your question
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(5 x 10^4) (9.46 x 10^12) in scientific notation
Alina [70]

Answer:

5

2.2704*10 hope it helps

3 0
3 years ago
4 question in one 65 points
jeka94

Q6.

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have: slope m = 3, y-intercept (0, 4) → b= 4

<h3>Answer: y = 3x + 4</h3>

Q7.

2x + 4y = 4     |subtract 2x from both sides

4y = -2x + 4     |divide both sides by 4

y = -0.5x + 1

Only second graph has y-intercept = 1.

<h3>Answer: The second graph.</h3>

Q8.

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have

(-16,\ 8)\to x_1=-16,\ y_1=8\\(4,\ -2)\to x_2=4,\ y_2=-2

Substitute:

m=\dfrac{-2-8}{4-(-16)}=\dfrac{-10}{20}=-\dfrac{1}{2}\\\\y-8=-\dfrac{1}{2}(x-(-16))\\\\y-8=-\dfrac{1}{2}(x+16)

<h3>Answer: The first equation.</h3>

Q9.

It's a vertical line. The equation of a vertical line is x = <em>a</em>, where <em>a</em> is any real number.

<h3>Answer: x = -4</h3>
6 0
3 years ago
Read 2 more answers
Please someone help me with this please
Elodia [21]
Help u with what I need to know what u need help on
3 0
3 years ago
Rich measured the height of a desk to be 80.7 cm. The actual height of the desk is 80 cm. What is Rich's percent error in this c
Hitman42 [59]

Answer:

0.9%

Step-by-step explanation:

We have been given that Rich measured the height of a desk to be 80.7 cm. The actual height of the desk is 80 cm.

We will use percentage error formula to solve our given problem.

\text{Percentage error}=\frac{\text{Experimental value-Actual value }}{\text{Actual actual}}\times 100

\text{Percentage error}=\frac{80.7-80}{80}\times 100

\text{Percentage error}=\frac{0.7}{80}\times 100

\text{Percentage error}=0.00875\times 100

\text{Percentage error}=0.875\approx 0.9

Therefore, Rich's percent error in calculation is 0.9%.

5 0
3 years ago
Find the area of this figure. Please show work if you can!
Yuri [45]
Here is the answer if you can't read my writing than just ask. also if you have any questions about how I got something feel free to ask

8 0
3 years ago
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