Step-by-step explanation:
answer: 135 degrees for the missing side
There's nothing preventing us from computing one integral at a time:
Expand the integrand completely:
Then
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
Answer:
x = - 4
Step-by-step explanation:
The first term is 2 and the 20th term is 1048576 .
<u>Step-by-step explanation:</u>
Here we have , If the sum of the first 12 terms of a geometric series is 8190 and the common ratio is 2. We need to Find the first term and the 20th term. Let's find out:
We know that Sum of a GP is :
⇒ 
So ,Sum of first 12 terms is :
⇒ 
⇒ 
⇒ 
⇒ 
Now , nth term of a GP is
⇒ 
So , 20th term is :
⇒ 
⇒ 
⇒ 
Therefore , the first term is 2 and the 20th term is 1048576 .
