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Romashka-Z-Leto [24]
3 years ago
5

Simplify quantity 9 x squared plus 12 end quantity over 6 9x + 2 x + 2 quantity 3 x squared plus 4 end quantity over 2 quantity

3 x squared plus 12 end quantity over 2
Mathematics
2 answers:
alexandr1967 [171]3 years ago
7 0

Answer:

3x^2 + 4

-------------

     2

grigory [225]3 years ago
5 0

15x

hope that help mm mm bkhbjbmjnm gdingf sfdsdb fdssv fsd

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Tell whether the angles are complementary or supplementary. Then fir<br> the value of x.
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Answer:

Step-by-step explanation:

4. 10x + 30 = 90

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2 years ago
A fair die is cast four times. Calculate
azamat

Answer:

I'd say that is an "occupancy problem".

I ran a spreadsheet simulation of that and I'd say the probability is approximately .13

Those problems are rather complex to solve.  What I think you would have to do is calculate the probability of  

A) ZERO sixes appearing in 4 rolls.

B) exactly 1 six appears in 4 rolls.

C) exactly 2 sixes appear in 4 rolls.

D) exactly 3 sixes appear in 4 rolls. and

E) exactly 4 sixes appear in 4 rolls.

4 rolls of a die can produce 6^4 or 1,296 combinations.

A) is rather easy to calculate:  The probability of NOT rolling a six in one roll is 5/6.  In 4 rolls it would be (5/6)^4 = 0.4822530864

E) is fairly easy to calculate: The probability of rolling one six is (1/6).  The probability of rolling 4 sixes is (1/6)^4 = 0.0007716049

Then we need to:

D) calculate how many ways can we place 3 objects into 4 bins

C) calculate how many ways can we place 2 objects into 4 bins

B)  calculate how many ways can we place 1 objects into 4 bins

I don't know how to calculate D C and B

Step-by-step explanation:

3 0
4 years ago
Please help problem below 15 POINTS!!
solniwko [45]

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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