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2 years ago

Pls help me out on this ill will give brainiest for the best answer

Mathematics

1 answer:

Svetach [21]2 years ago

7 0

Answer:

Step-by-step explanation:

butt

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Find the answer for x that makes this number sentence true: 2x + 9 > 11

Nana76 [90]

Answer:

2 x 2 + 9 > 11

2 x 2 = 4

4 + 9 = 13

13 > 11

Therefore, x = 2.

Step-by-step explanation:

I hope this helps! ^w^

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3 years ago

Fill in the missing terms for the geometric sequence

expeople1 [14]

Step-by-step explanation:

11/2, -11, 22, -44, 88, -176

common ratio : 22/(-11) = -2

4 0

3 years ago

I need help with the problem below Pls dont spam random letters :) 2 1/7 :(1.5a)= 5/14 :0.8

snow_lady [41]

Answer:

Step-by-step explanation:

56 1/2 because i did the math

7 0

3 years ago

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

4 0

2 years ago

What is -5(2a-3b)+5(3b-2a) simplified?

KIM [24]

-10a+15b + 15b-10a = -20a+30b

5 0

3 years ago

Read 2 more answers