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3 years ago

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Rachel deposits $100 in a bank account and she gets 8% simple interest on it. Which linear model gives the return on her investm

ent in terms of time t in years?
a. R = 8t – 100
b. R = 8t + 100
c. R = 2t + 100
d. R = 88t + 100
e. R = 3t + 108

1 answer:

Mandarinka [93]3 years ago

3 0

The answer would be B because the 100 stays in there and you are adding 8% per year. Hope this helps.

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If tu=18 and u=11 what is tv

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If the point U is between points T and V, then the numerical length of TV is 29 units

<h3>How to determine the numerical length of segment TV?</h3>

From the question, we have the following lengths that can be used in our computation:

Length TU = 18 units
Length UV = 11 units

The above parameters and representations implies that the point U is between endpoints T and V

This also means that the length TV is longer than the other lengths TU and TV

So, we have the following length equation

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Read more about lengths at

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<u>Possible question</u>

If tu = 18 and uv = 11 what is tv, if point u is between points t and v

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9 months ago

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3 years ago

A high school student took two college entrance exams, scoring 1070 on the SAT and 25 on the ACT. Suppose that SAT scores have a

antoniya [11.8K]

Answer:

Due to the higher z-score, he did better on the SAT.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Determine which test the student did better on.

He did better on whichever test he had the higher z-score.

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Scored 1070, so $X = 1070$

SAT scores have a mean of 950 and a standard deviation of 155. This means that $\mu = 950, \sigma = 155$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1070 - 950}{155}$

$Z = 0.77$

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Scored 25, so $X = 25$

ACT scores have a mean of 22 and a standard deviation of 4. This means that $\mu = 22, \sigma = 4$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 22}{4}$

$Z = 0.75$

Due to the higher z-score, he did better on the SAT.

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