Answer:
Step-by-step explanation:
Consider that F(x,y,z) = (x + y, y + z, z + z)
![r(t)=(cos t,4sint,\sqt{5}cost)\\r'(t)=(-sint,4cost,-\sqrt{5}sint)\\F(r(t))=[tex]\int\limits^{2\pi}_0 {F(r(t))r'(t)} \, dt \\\\=\int\limits^{2\pi}_0(cost+4sint,4sint+\sqrt{5}cost+cost)(-sint,4cost,-\sqt{5}sint)dt\\\\=\int\limits^{2\pi}_0(-sintcost-4sin^2t+16costsint+4\sqrt{5}cos^2t-5sintcost-\sqrt{5}sintcost)dt\\\\=\int\limits^{2\pi}_0(10sintcost-4sin^2t+4\sqrt{5}cos^2t-\sqrt{5}sintcost)dt\\\\=\int\limits^{2\pi}_0((10-\sqrt{5})sintcost-(4+4+\sqrt{5})sin^2t+4\sqrt{5})dt\\\\(10-\qrt{5})(0)-(4+4+\sqrt{5}(\pi)+4\sqrt{5}(2\pi)\\\\(\sqrt{5}-1)4\pi)](https://tex.z-dn.net/?f=r%28t%29%3D%28cos%20t%2C4sint%2C%5Csqt%7B5%7Dcost%29%5C%5Cr%27%28t%29%3D%28-sint%2C4cost%2C-%5Csqrt%7B5%7Dsint%29%5C%5CF%28r%28t%29%29%3D%5Btex%5D%5Cint%5Climits%5E%7B2%5Cpi%7D_0%20%7BF%28r%28t%29%29r%27%28t%29%7D%20%5C%2C%20dt%20%5C%5C%5C%5C%3D%5Cint%5Climits%5E%7B2%5Cpi%7D_0%28cost%2B4sint%2C4sint%2B%5Csqrt%7B5%7Dcost%2Bcost%29%28-sint%2C4cost%2C-%5Csqt%7B5%7Dsint%29dt%5C%5C%5C%5C%3D%5Cint%5Climits%5E%7B2%5Cpi%7D_0%28-sintcost-4sin%5E2t%2B16costsint%2B4%5Csqrt%7B5%7Dcos%5E2t-5sintcost-%5Csqrt%7B5%7Dsintcost%29dt%5C%5C%5C%5C%3D%5Cint%5Climits%5E%7B2%5Cpi%7D_0%2810sintcost-4sin%5E2t%2B4%5Csqrt%7B5%7Dcos%5E2t-%5Csqrt%7B5%7Dsintcost%29dt%5C%5C%5C%5C%3D%5Cint%5Climits%5E%7B2%5Cpi%7D_0%28%2810-%5Csqrt%7B5%7D%29sintcost-%284%2B4%2B%5Csqrt%7B5%7D%29sin%5E2t%2B4%5Csqrt%7B5%7D%29dt%5C%5C%5C%5C%2810-%5Cqrt%7B5%7D%29%280%29-%284%2B4%2B%5Csqrt%7B5%7D%28%5Cpi%29%2B4%5Csqrt%7B5%7D%282%5Cpi%29%5C%5C%5C%5C%28%5Csqrt%7B5%7D-1%294%5Cpi%29)
[/tex]
Answer:
Step-by-step explanation:
The graph is skewed to the right.
There isn’t enough information for us to help you:(
Answer:
given,triangle EFG is congruent to triangle HIJ,THEIR corresponding sides are equal,
so, 10x=x+45
10x_x=45
or,9x=45
therefore , x=5
again,
3y = y+14
or, 3y_y=14
or, y=14/2
therefore the value of y is 7.
so the value of x is 5 and y is 7.
hope its helpful to uh...
Answer:
∠ADB≅∠ABC by the Alternate Interior Angles Theorem
∠CAD≅∠ACB by the Alternate Interior Angles Theorem
∠BAD and ∠ADV are supplementary by the Consecutive Interior Angle Theorem
∠ABC and ∠BCD are supplementary by the Consecutive Interior Angle Theorem
