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Len [333]
3 years ago
5

Each week Thomas will double the amount of money in his bank. What type of function is represented by this situation

Mathematics
1 answer:
babunello [35]3 years ago
5 0

Answer:

An exponential growth.

Step-by-step explanation:

We know that each week, Thomas will double the amount of money in his bank.

Let's assume that in week 0, he has an amount A of money in his bank.

After one week, in week number 1 (w = 1), the amount of money is doubled, so if we define the function M(w) as the amount of money as a function of the number of weeks, we will have:

M(1) = 2*A

After another week, in w = 2, the amount of money is doubled again, so here we have:

M(2) = 2*(M(1)) = 2*(2*A) = A*2^2

After another week, at w = 3, the amount of money is doubled again:

M(3) = 2*(M(2)) = 2*(A*2^2) = A*2^3

We already can see the pattern here, we can expect that for the week w, the amount of money in the account is given by:

M(w) = A*2^w

This is an exponential equation (an exponential growth to be more specific), so the type of function that is represented by this situation is an exponential growth.

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GuDViN [60]
Since you have to multiple. L×W×H....

The first one has a volume of 400 and the second has a volume of 400...so both prisms have an equal volume but have a differnet shape
7 0
3 years ago
(X+5)+(x-5)=56 what does x=?
kirill115 [55]

Answer:

x=28

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+5+x−5=56

x+5+x+−5=56

(x+x)+(5+−5)=56(Combine Like Terms)

2x=56

2x=56

Step 2: Divide both sides by 2.

2x/2=56/2

x=28

plz give me brainiest

8 0
3 years ago
HELP ASAP PLEASE.
nordsb [41]
The range of the primary phone data is 0.28. 
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.

To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28

To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73

To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12

To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6

The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
5 0
3 years ago
Read 2 more answers
How do I solve this??
WITCHER [35]

Answer:

Step-by-step explanation:

Formula

Sn = (a + a + (n - 1)*d) * n / 2

Givens

Sn = 60

a =  3

Solution

You want integer values for d and n

60 = (2*a + (n - 1)*d) * n/2           Multiply both sides by 2

120 = (2*3 + (n - 1)*d ) * n    

120 = (6 + n*d - d) * n

120 = 6n + n^2*d - d*n

This gives some really wild results. I will list all of them here. and then discuss them.

These are the ones that give results without any question and are correct.

n         d         tn

2         54         3  57

3          17         3    20   37

4           8         3    11   19   27

Here are some that are the gift of the equation

20         0           3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3

Now the equation says the following 3 are correct, but are they? Can you have a negative n? The equation says yes, but I doubt your instructor will.

-5         5          

-1         63

-2        22

You can bring these up if you are in a classroom. I wouldn't if you have to submit this to a computer which has absolutely no ability whatever to think about exceptions. Even the 20 0 is one I wouldn't use.

7 0
3 years ago
I need help on seeing if my answers are correct or not !
TEA [102]

Answer:

false false false true true

Step-by-step explanation:

you got the first four wrong.

6 0
2 years ago
Read 2 more answers
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