What is the order, from narrowest to widest graph, of the quadratic functions f(x) = –10x², f(x) = 2x², f(x) = 0.5x²?
1 answer:
You might be interested in
The equations are
,
The graphs of the solutions (x, y) of these equations are 2 parabolas, since the right hand side expressions are polynomials of degree 2.
The solution/s of the system are the x-coordinates of the point/s of intersection of the parabolas.
The solutions of the first equation form a parabola looking downwards (since the coefficient of x^2 is -), and the second, a parabola opening upwards (since the coefficient of x^2 is +).
We can draw both parabolas, but to find the solution we still need to solve the system algebraically.
The algebraic solution of the system is:
, so
the solutions are x=-1 and x=1.
The graph of the system is drawn using desmos.com
If we are allowed to use a graphic calculator, we can draw both graphs and point at the solution.
The graphs of the solutions (x, y) of these equations are 2 parabolas, since the right hand side expressions are polynomials of degree 2.
The solution/s of the system are the x-coordinates of the point/s of intersection of the parabolas.
The solutions of the first equation form a parabola looking downwards (since the coefficient of x^2 is -), and the second, a parabola opening upwards (since the coefficient of x^2 is +).
We can draw both parabolas, but to find the solution we still need to solve the system algebraically.
The algebraic solution of the system is:
the solutions are x=-1 and x=1.
The graph of the system is drawn using desmos.com
If we are allowed to use a graphic calculator, we can draw both graphs and point at the solution.
Answer:
Step-by-step explanation:
Vertex form of a quadratic is given by:
Where (h, k) is the vertex and <em>a</em> is the leading coefficient.
We are given that the vertex is (3, 1). Hence, <em>h</em> = 3 and <em>k </em>= 1. By substitution:
We are also given a point (2, -6). This means that when <em>x </em>= 2, <em>f(x)</em> = -6. Hence:
Solve for <em>a</em>. Subtract:
Simplify:
Therefore:
Hence, our quadratic is: