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3 years ago

What is the order, from narrowest to widest graph, of the quadratic functions f(x) = –10x², f(x) = 2x², f(x) = 0.5x²?

Mathematics

1 answer:

Korvikt [17]3 years ago

6 0

Answer:

From narrowest to widest graph, the order is f(x) = –10x², f(x) = 2x², f(x) = 0.5x²

Step-by-step explanation:

I graphed the functions below

f(x) = –10x² is the black line, f(x) = 2x² is the red line, and f(x) = 0.5x² is the blue line.

If this answer is correct, please make me Brainliest!

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as a sum, difference,

Leya [2.2K]

Answer: $\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]$

Step-by-step explanation:

Properties of logarithm :

$\log (ab)= \log a+\log b$
$\log(\dfrac{a}{b})=\log a-\log b$
$\log a^n= n\log a$

The given expression in terms of Natural log : $\ln (x^2 - 1)^{\frac{1}{3}}$

This will become $\dfrac{1}{3}\ln (x^2 - 1)$ [ By using Property (3)]

$=\dfrac{1}{3}\ln (x^2-1^2)$

$=\dfrac{1}{3}\ln ((x+1)(x-1))$ [ $\because a^2-b^2=(a+b)(a-b)$ ]

$=\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]$ [ By using Property (1)]

Hence, the simplified expression becomes $\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]$ .

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3 years ago