Answer:
Y~x
Y = k × v
Y = 22
Step-by-step explanation:
Y~ x
Y = k × X
Since the question isn't complete,we are going to assign figures to complete this very question and move on to other things and you can as well solve questions that are similar to this ones.
Now let's assume that the question says that is 6 when x is 3,what is y when x is 11.
To solve this question above,we need to find the constant of variation which will then enable us to know what y is when x is 11
Y~ x
Y = k × V
When y is 6 and x is 3,k will be
6 = 3k
K= 2
Now when k is 2,x is 11,y Will then be
Y = kx
Y = 2 × 11
Y = 22.
With this procedure,one can find any value of x or y when they have the constant of variation.
If you have a figure assigned to x and y is to be found,the constant of variation will help to get y and vice versa
Answer:

Step-by-step explanation:
Parallel => <u><em>This means it has the same slope as this one.</em></u>
Slope = m = 1
Now,
Point = (x,y) = (-6,2)
So, x = -6, y = 2
<u><em>Putting this in slope intercept form to get b</em></u>

=> 2 = (1)(-6) + b
=> b = 2+6
=> b = 8
<u><em>Now putting m and b in the slope-intercept form to get the required equation:</em></u>
=> 
=> 
Answer: x > 486
Explanation:
We have some number x and we divide that by 18. The result is larger than 27. To find possible values for x, we need to undo what is happening to x. The opposite of division is multiplication. We multiply both sides by 18 to cancel out the "18" on the left side, which will isolate x to get it to its own side.
This is what the steps look like
x/18 > 27
18*( x/18 ) > 18*27 .... multiplying both sides by 18
x > 486 ... note the 18's cancel on the left side
So this means x is some number greater than 486.
If those two are your only choices then the answer is
none of the above.
<em>Attached is a cumulative frequency table for your data.</em> If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong.
The answer is then none of the above or find one that matches the table attached.
Answer:
45
Step-by-step explanation:
Given that the number of savory dishes is 9 and the number of sweet dished is 5.
Denoting all the 9 savory dishes by
, and all the sweet dishes by
.
The possible different mix-and-match plates consisting of two savory dishes are as follows:
There are 9 plates with
from sweet plates which are 
There are 9 plates with
from sweet plates which are 
Similarly, there are 9 plated for each
and 
Hence, the total number of the different mix-and-match plates consisting of two savory dishes
