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3 years ago

Please help!!!!!!!!!!!!

Mathematics

2 answers:

MaRussiya [10]3 years ago

5 0

Answer:

5 cm, 12in, 3.5 yrds

Step-by-step explanation:

to find the radius you divide the diamenter by 2.

Free_Kalibri [48]3 years ago

3 0

Answer:

a) 5 cm b) 12in c) 7yd

I think it's so simple. Anyways

This is your answer. If I'm right so,

Please mark me as brainliest. thanks!!!

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A music store bought a CD set at a cost of $20. When the store sold the CD set, the percent markup was 40%. Find the selling pri

attashe74 [19]

Answer:

20 * 1.4 = 28

Step-by-step explanation:

8 0

3 years ago

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PLEASE HELP!!!

Anettt [7]

Answer:

Answer is 5 inches on edg

Step-by-step explanation:

6 0

4 years ago

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There are 10 marbles in a bag. Four are blue, 3 are black and 2 white and 1 red. If the marbles are not replaced once they are d

stich3 [128]

Given:

Given that there are 10 marbles in a bag. 4 are blue, 3 are black, 2 are white and 1 is red.

The marbles are selected by not replacing the drawn ones.

We need to the probability of selected a black marble and then a white marble without replacement.

Probability:

Let B denote the black marble.

Let W denote the white marble.

The probability of selecting a black marble is $P(B)=\frac{3}{10}$

The probability of selecting a white marble without replacement is $P(W)=\frac{2}{9}$

The probability of selecting a black marble and then a white marble without replacement is given by

$P(B \ and \ W)=P(B) \cdot P(W)$

Substituting the values, we get;

$P(B \ and \ W)=\frac{3}{10} \cdot \frac{2}{9}$

$P(B \ and \ W)=\frac{6}{90}$

$P(B \ and \ W)=\frac{1}{15}$

Thus, the probability of selecting a black marble and then a white marble without replacement is $\frac{1}{15}$

4 0

3 years ago

A collection of 33 coins having dimes quarters and nickels, there are 3 times more nickels then dimes and half the amount of dim

zloy xaker [14]

Answer:

Each coins are quarters of 6, nickels of 18 and the dimes of 9.

Step-by-step explanation:

There is a mistake in question.

The question must be:

A collection of 33 coins having dimes quarters and nickels, there are 3 times as many nickels as quarters, and one-half as many dimes as nickels, all of the coins equal $3.30 how many coins of each kind are there?

Now, to find the number coins of each.

Let the quarters be $x$ .

Nickels be $3x$ .

And the dimes be $\frac{3x}{2}$ .

So, the total collection of coins are:

$x+3x+\frac{3x}{2} =33.$

On adding the fractions we get:

$\frac{2x+6x+3x}{2} =33$

$\frac{11x}{2} =33$

Multiplying both sides by 2 we get:

$11x=66$

Dividing both sides by 11 we get:

$x=6.$

Thus, quarters = 6.

Nickels = $3x=3\times 6=18.$

Dimes = $\frac{3x}{2} =\frac{3\times 6}{2} =\frac{18}{2}=9 .$

Therefore, each coins are quarters of 6, nickels of 18 and the dimes of 9.

3 0

3 years ago

What is the least common denominator of the rational expressions below?

Lyrx [107]

Answer:

B.(x-6)

Step-by-step explanation:

12/(x^2 - 11x+30) - 43/(x^2-6x)

12/((x - 5) (x - 6)) - 43/x(x-6) [Factoring the denominator]

Both have x-6 common in the denominator,

4 0

3 years ago