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3 years ago

Which expressions are equivalent to (13x+x−53x)−(−43x+2) ?

Mathematics

1 answer:

RoseWind [281]3 years ago

5 0

Answer:

4x+2

Step-by-step explanation:

(13x+x−53x)−(−43x+2)

Group all the same variables on each side.

(-39x)-(-43x+2)

-39x+43x+2

4x+2

Hope this helps :)

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What's (7 x 100) + (4 x /100) + (8 x 1/1000) in standard form?

IceJOKER [234]

Answer:

(7*100) can be written as 7*10^2

4 * / 100 i don’t know

if it was 4 * 100 then it’s 4*10^2

if it was divided then it’s 4*10^-2

8* 1/1000 = 8/1000 = 8*10^-3

add together to get 1.100008 * 10^3 (if it was 4*100)

or 7.00048 * 10^2 ( if it was 4/100)

7 0

3 years ago

Find the solution of the given initial value problem: y''- y = 0, y(0) = 2, y'(0) = -1/2

igor_vitrenko [27]

Answer: The required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Step-by-step explanation: We are given to find the solution of the following initial value problem :

$y^{\prime\prime}-y=0,~~~y(0)=2,~~y^\prime(0)=-\dfrac{1}{2}.$

Let $y=e^{mx}$ be an auxiliary solution of the given differential equation.

Then, we have

$y^\prime=me^{mx},~~~~~y^{\prime\prime}=m^2e^{mx}.$

Substituting these values in the given differential equation, we have

$m^2e^{mx}-e^{mx}=0\\\\\Rightarrow (m^2-1)e^{mx}=0\\\\\Rightarrow m^2-1=0~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mx}\neq0]\\\\\Rightarrow m^2=1\\\\\Rightarrow m=\pm1.$

So, the general solution of the given equation is

$y(x)=Ae^x+Be^{-x},$ where A and B are constants.

This gives, after differentiating with respect to x that

$y^\prime(x)=Ae^x-Be^{-x}.$

The given conditions implies that

$y(0)=2\\\\\Rightarrow A+B=2~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

and

$y^\prime(0)=-\dfrac{1}{2}\\\\\\\Rightarrow A-B=-\dfrac{1}{2}~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

Adding equations (i) and (ii), we get

$2A=2-\dfrac{1}{2}\\\\\\\Rightarrow 2A=\dfrac{3}{2}\\\\\\\Rightarrow A=\dfrac{3}{4}.$

From equation (i), we get

$\dfrac{3}{4}+B=2\\\\\\\Rightarrow B=2-\dfrac{3}{4}\\\\\\\Rightarrow B=\dfrac{5}{4}.$

Substituting the values of A and B in the general solution, we get

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

Thus, the required solution of the given IVP is

$y(x)=\dfrac{3}{4}e^x+\dfrac{5}{4}e^{-x}.$

4 0

3 years ago

NoT YellInG ThIS IS JuSt TO AtTRaCT AtTeNTiOn 50 POiNtS PLeaSE ANswER I Am NoT WasTiNg PoInTS!!! Find the range of 1 1/4, 5/8, 3

Arada [10]

Answer:

Range = 1 1/4

Step-by-step explanation:

Range = Maximum - Minimum

Arranging the data in ascending order :

1/2, 5/8, 3/4, 1 1/4, 1 1/2, 1 3/4

Solving for range :

Range = 1 3/4 - 1/2
Range = 1 3/4 - 2/4
Range = 7/4 - 2/4
Range = 5/4
Range = 1 1/4

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2 years ago

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uysha [10]

Answer:

i put it in the comments bc someone was answering but 150 lol

Step-by-step explanation:

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3 years ago

Jojo, my cat, had eight kittens. Three were black with white spots. Four were all black. The last one was gray. What is the rati

Ann [662]

4:8 simplified to 1:2

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3 years ago

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