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Ierofanga [76]
3 years ago
9

Help me please is this right

Mathematics
1 answer:
slavikrds [6]3 years ago
7 0
The answer is 7.5 eeeee
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If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (u/v)(x)
choli [55]

Answer:

c) -x^3 + x^2 - 1

Step-by-step explanation:

Given: u (x) = x^5 - x^4 +x^2 and v(x) = -x^2

(u/v)(x) = u(x)/v(x)

Now plug in the given functions in the above formula, we get

= (x^5 - x^4 + x^2) / -x^2

We can factorize the numerator.

In x^5 - x^4 + x^2. the common factor is x^2, so we can take it out and write the remaining terms in the parenthesis.

= x^2 (x^3 - x^2 + 1) / - x^2

Now we gave x^2 both in the numerator and in the denominator, we can cancel it out.

(u/v)(x) = (x^3 - x^2 + 1) / -1

When we dividing the numerator by -1, we get

(u/v)(x) = -x^3 + x^2 - 1

Answer: c) -x^3 + x^2 - 1

Hope you will understand the concept.

Thank you.

6 0
4 years ago
Read 2 more answers
Which of the following have both 2 and -5 as solutions.
Stella [2.4K]
x_1=2;\ x_2=-5\\\\(x-2)(x-(-5))=(x-2)(x+5)=x^2+5x-2x-10=x^2+3x-10\\\\Answer:a.
3 0
4 years ago
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The amount of time it takes Isabella to wait for the bus is continuous and uniformly distributed between 3 minutes and 17 minute
Arturiano [62]

Answer:

P(X>5) = 0.857

Step-by-step explanation:

Let X \sim uniform(3.17)

f(x) = \dfrac{1}{17-3}   ; \ \ \ 3 \le x \le 17

The required probability that it will take Isabella more than 5 minutes to wait for the bus can be computed as:

P(X > 5) =  \int ^{17}_{5} f(x) \ dx

P(X > 5) =  \int ^{17}_{5} \dfrac{1}{17-3} \ dx

P(X > 5) =\dfrac{1}{14}  \Big [x \Big ] ^{17}_{5}

P(X > 5) =\dfrac{1}{14} [17-5]

P(X > 5) =\dfrac{12}{14}

P(X>5) = 0.857

6 0
3 years ago
I need help I will give 100 points and brainliest
Anit [1.1K]

Answer:

5. 9/2 6. 9/4 7. 7/2 8. 8/3 9. 2/3

Step-by-step explanation:

Hope I helped!!

4 0
3 years ago
Read 2 more answers
The path of a skateboarder can be modeled by the equation (x – 3)2 = –8(y – 8), where distance is in feet and air resistance is
yKpoI14uk [10]

The maximum height and horizontal distance is required.

Maximum height 8 feet; horizontal distance 16 feet

The given path is (x-3)^2=-8(y-8)

If the skateboarder jumps at x = 0 she will land at y = 0. However there will be at horizontal displacement.

(x-3)^2=-8(0-8)\\\Rightarrow (x-3)^2=8^2\\\Rightarrow x-3=\pm 8\\\Rightarrow x-3=8\\\Rightarrow x=11

or

x-3=-8\\\Rightarrow x=-5

The distance between -5 and 11 is 11-(-5)=16

Middle point would be \dfrac{16}{2}=8 from -5.

-5+8=3

So, x=3

The maximum height will be

(3-3)^2=-8(y-8)\\\Rightarrow y-8=0\\\Rightarrow y=8

The maximum height is 8 feet and the horizontal distance is 16 feet.

Learn more:

brainly.com/question/25227606

brainly.com/question/13103131

6 0
3 years ago
Read 2 more answers
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