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Nostrana [21]
3 years ago
14

The amount of time it takes Isabella to wait for the bus is continuous and uniformly distributed between 3 minutes and 17 minute

s. What is the probability that it takes Isabella more than 5 minutes to wait for the bus
Mathematics
1 answer:
Arturiano [62]3 years ago
6 0

Answer:

P(X>5) = 0.857

Step-by-step explanation:

Let X \sim uniform(3.17)

f(x) = \dfrac{1}{17-3}   ; \ \ \ 3 \le x \le 17

The required probability that it will take Isabella more than 5 minutes to wait for the bus can be computed as:

P(X > 5) =  \int ^{17}_{5} f(x) \ dx

P(X > 5) =  \int ^{17}_{5} \dfrac{1}{17-3} \ dx

P(X > 5) =\dfrac{1}{14}  \Big [x \Big ] ^{17}_{5}

P(X > 5) =\dfrac{1}{14} [17-5]

P(X > 5) =\dfrac{12}{14}

P(X>5) = 0.857

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Answer:

the probability that Jack draws the blue ball is 0.38539

Step-by-step explanation:

Given the data in the question;

box contains

blue balls = 5

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Jim and Jack start drawing balls from the box, respectively, one at a time, at random, and without replacement

Now,

on the first attempted;

⇒ ( 8/13) × ( 5/12) = 10/39  

on the second attempt;

⇒ ( 8/13 ) ( 7/12) ( 6/11 ) ( 5/10 ) = 14/143

on the third attempt;

⇒ ( 8/13 ) ( 7/12) ( 6/11 ) ( 5/10 ) ( 4/9 ) ( 5/8 ) = 35/1287

on the fourth attempt;

⇒  ( 8/13 ) ( 7/12) ( 6/11 ) ( 5/10 ) ( 4/9 ) ( 3/8 ) ( 2/7 ) ( 5/6 ) = 5/1287

so we add everything;  

⇒ 10/39 + 14/143 + 35/1287 + 5/1287

= 0.38539

Therefore, the probability that Jack draws the blue ball is 0.38539

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