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3 years ago

Which of the following statements is/are TRUE about diagonals of special parallelograms?

Mathematics

1 answer:

Ilia_Sergeevich [38]3 years ago

4 0

Answer:

I, II and IV

Step-by-step explanation:

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Y to the 3rd power times y to the negative 5th power

lina2011 [118]

Y^3 * y^5 = y^8. you add the exponents

8 0

3 years ago

Which ordered pair is a solution to the system of linear equations? 2x + 3y= 6 –3x + 5y = 10

n200080 [17]

Answer:

(0,2)

Step-by-step explanation:

solve by addition/elimination

2x + 3y= 6

–3x + 5y = 10

multiply first equation by 3 and second one by 2 to eliminate x)

6x+9y=18

-6x+10y=20 (add the two equations)

6x+9y-6x+10y=38

19y=38

y=38/19=2

2x+3y=6

2x=6-6

x=0

7 0

3 years ago

Subtract 10x - 7 from 2x – 6.

hichkok12 [17]

(2x - 6) - (10x - 7) # Starting expression

-8x - 1 # Combine like terms

Final answer:

-8x - 1

Hope this helps!

8 0

3 years ago

Read 2 more answers

Directions: for questions 1 through 4, find the diagonal length of each solid figure.

Alex787 [66]

$\text{The length of the diagonal is }11.2\text{ mm}$

Here, we want to find the diagonal of the given solid

To do this, we need the appropriate triangle

Firstly, we need the diagonal of the base

To get this, we use Pythagoras' theorem for the base

The other measures are 6 mm and 8 mm

According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides

Let us have the diagonal as l

Mathematically;

$\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}$

Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above

Thus, we calculate this using the Pytthagoras' theorem as follows;

$\begin{gathered} d^2=5^2+10^2 \\ d^2\text{ = 25 + 100} \\ d^2\text{ = 125} \\ d\text{ = }\sqrt[]{125} \\ d\text{ = }11.2\text{ mm} \end{gathered}$

7 0

1 year ago

Write the expression 44(4–7)(4) using a single exponent.

Ghella [55]

<h3>The given expression as single exponent is:</h3>

$4^4 \times 4^{-7} \times 4 = 4^{-2}$

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

$4^4 \times 4^{-7} \times 4$

In exponents,

When the base is same, exponents can be added

Which means,

$a^m \times a^n = a^{m+n}$

Therefore,

$4^4 \times 4^{-7} \times 4 = 4^{4-7+1}\\\\Simplify\\\\4^4 \times 4^{-7} \times 4 = 4^{-3+1} \\\\4^4 \times 4^{-7} \times 4 = 4^{-2}$

Thus the given expression as single exponent is:

$4^4 \times 4^{-7} \times 4 = 4^{-2}$

8 0

3 years ago

Read 2 more answers