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3 years ago

15

The sum of a number and twice a second number is 29. The second number is ten less than three times the first number. What are t

he two numbers?
Also, write the two equations.

1 answer:

katovenus [111]3 years ago

8 0

the sum of a number and twice a second number

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Amaya used these steps to solve the equation 8x+4=9+4(2x−1). Which choice describes the meaning of her result, 4=5?

GREYUIT [131]

Answer:

no values of x make the equation true

Step-by-step explanation:

Given that her work is correct, then the final step gives

4 = 5 ← meaningless

This indicates that the equation has no solution

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Write the equation of the line that passes through the points (3,4) and (1,5)

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Hi,

$y= -\frac{1}{2} x+b$

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Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4

steposvetlana [31]

$f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}$

$\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}$

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What percent of the respondents preferred dark chocolate or milk chocolate?

Wewaii [24]

80%, 1000-200 = 800/1000 or 80%

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2 years ago

The following diagram shows parallel lines cut be a transversal. What is the measure of Angle 2?

Crank

2x + 100 = 5x + 55
3x = 45
x = 15

2(15) + 100 = 130

180-130 = 50

so angle 2 is 50 degrees

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3 years ago