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3 years ago

What does the following loop do? val = 0 total = 0 while (val < 10): val = val + 1 total = total + val print(total)

Computers and Technology

1 answer:

labwork [276]3 years ago

4 0

Program in Python

val = 0

total = 0

while (val < 10):

val = val + 1

total = total + val

print(total)

Answer:

Prints the sum of the numbers from 1 to 10.

Explanation:

Given

The above lines of code

Required

What does the loop do?

To know what the loop does, we need to analyze the program line by line

The next two lines initialize val and total to 0 respectively

val = 0

total = 0

The following iteration is repeated while val is less than 10

while (val < 10):

This increases val by 1

val = val + 1

This adds val to total

total = total + val

This prints the value of total

print(total)

Note that the loop will be repeated 10 times and in each loop, val is incremented by 1.

The values of val is 1 to 10.

The summation of these value is then saved in total and printed afterwards.

Hence, the loop adds numbers from 1 to 10

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3 years ago

Suppose that you are asked to modify the Stack class to add a new operation max() that returns the current maximum of the stack

Advocard [28]

Answer:

Following are the code to the given points:

Explanation:

For point 8.1:

public String max()//defining a method max

{

String maxVal=null;//defining a string variable that holds a value

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{

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{

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}

For point 8.2:

public void push(String item)//defining a method push that accepts item value in a parameter

{

a[n]=item;//defining an array to hold item value

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{

maxVals[n]=item;//holding item value in maxVals variable

}

else

{

maxVals[n]=maxVals[n-1];//decreasing the maxVals value

}

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}

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{

return a[--n];//use return value

}

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{

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}

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7 0

3 years ago

The following code does not work as intended. It is meant to input two test grades and return the average in decimal format:

vredina [299]

Answer:

Type casting error

Explanation:

Logically, the program is correct and it is expected to return the average value. However, test1 and test2 are int values and when you applies any algebraic expression on Int, it will result into Int.

So, in this part (test1 + test2 )/2, two integers are adding and the final result is still an integer and this part will act as an integer even if you multiple or divide with any external number.

For example,

test1 = 4

test2 = 5

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Now, if you divide it by 2, it will still react as an integer portion. So, 9/2 would result in 4 instead of 4.5. All the calculation is done on the right side before assigning it to a double variable. Therefore, the double variable is still getting the int value and your program is not working correctly.

The solution is to typecast the "(test1 + test2 )/2" portion to double using Double.valueOf(test1 + test2)/2 ;

I have also attached the working code below.

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

System.out.println("Hello World");

Scanner scan = new Scanner (System.in);

int test1 = scan.nextInt();

int test2 = scan.nextInt();

double average = Double.valueOf(test1 + test2)/2 ;

System.out.println("Answer: " + average);

}

4 0

4 years ago