Answer:
d
Step-by-step explanation:
d
dkimiunuhbubhwswdqwduoewdWEC W vcuuhdcosv
Answer:
14
Step-by-step explanation:
An imaginary number " i " is the squared root of -1, so whenever you square i it's like squaring a squared root. The squared root would cancel and you would be left with just the number under it, that is, the -1.
i ^ 2 = -1
<h3>The equation is:</h3><h3>

</h3><h3>The number is 3 or 4</h3><h3><em><u>Solution:</u></em></h3>
Given that,
7 added to the square of a number is equal to 7 times the number, minus 5
Let "x" be the unknown number
From given,
7 added to square of x = 7 times the x minus, 5

Solve the above equation

Split the middle term

We have two solutions
x - 3 = 0
x = 3
And
x - 4 = 0
x = 4
Thus number is 3 or 4
for f(x) = -2(x-4)2+2 - set equation to y = -2(x-4)2+2, solve x-4=0, x = 4
axis of symmetry is x = 4
for g(x) = 5x2-10x+7, set equation to y = 5x2-10x+7, solve the square: 5x2 becomes 5(x-1)2 solve x-1 = 0, x = 1
axis of symmetry is x=1
for H(x) what x value would be the centerline so that the graph symmetry is the same on both sides? looking at the graph the top of the arc is on -2
so axis of symmetry is x = -2