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Dmitry_Shevchenko [17]
3 years ago
13

In math, state that are true for four number are called what?

Mathematics
1 answer:
bonufazy [111]3 years ago
8 0

Answer: wait

Step-by-step explanation:

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There is one side of the triangle that you can measure. Which side would it be? (XZ, XY, or ZY)
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In this right triangle, you are given the measurements for the hypotenuse, c, and one leg, b. The hypotenuse is always opposite the right angle and it is always the longest side of the triangle.
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Number x Number y which, when multiplied by itself, equals number x Square root y
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3 years ago
Solve the equation. And write all solutions in general form.
Amiraneli [1.4K]

Answer:

x = pi/2 + 2 pi n                            x = pi + 2 pi n   where n is an integer

x = 5pi /3 + 2 pi n                      

Step-by-step explanation:

8 cos^2 x + 4 cos x-4 = 0

Divide by 4

2 cos^2 x +  cos x-1 = 0

Let u = cos x

2 u^2 +u -1 =0

Factor

(2u -1) ( u+1) = 0

Using the zero product property

2u-1 =0    u+1 =0

u = 1/2      u = -1

Substitute cosx for u

cos x = 1/2    cos x = -1

Take the inverse cos on each side

cos ^-1(cos x) = cos ^-1(1/2)   cos ^-1( cos x) =cos ^-1( -1)

x = pi/2 + 2 pi n                            x = pi + 2 pi n   where n is an integer

x = 5pi /3 + 2 pi n                      

8 0
3 years ago
Create an equation of a line that crosses the y-axis at the origin and has a slope of 1/2
Salsk061 [2.6K]

Answer:

since the line goes through the origin you dont need a y intercept.

y= x/2

or y= 1/2 x

8 0
3 years ago
Help please! Thank you:)
Masja [62]

Answer:

what kind of math is that?

Step-by-step explanation:

7 0
3 years ago
PLZ help super fast thanks
Nikolay [14]

Answer:

B. \frac{1}{x^2y^7}

Step-by-step explanation:

Given:

(x^3y^{-2}z)(x^{-5}y^{-5}z^{-1})

Hence Solving the given expression we get;

By Law of Indices which states;

(a^xb^yc^z)(a^pb^qc^r) = a^{x+p}b^{y+q}c^{z+r}

Hence we get;

x^{3+(-5)}y^{(-2)+(-5)}z^{1+(-1)}\\\\x^{3-5}y^{-2-5}z^{1-1}\\\\x^{-2}y^{-7}

Also We know that

a^{-6} =\frac{1}{a^6}

So,

\frac{1}{x^2y^7}

8 0
3 years ago
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