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lawyer [7]
3 years ago
15

Can someone help me with my homework its experimental and theorectical probability

Mathematics
2 answers:
Makovka662 [10]3 years ago
6 0
Yes sure what’s the question?
PIT_PIT [208]3 years ago
5 0

Answer:

Step-by-step explanation:

fjfjgjgjghg

You might be interested in
What's the communitive property
Naddik [55]
Communitive property is the property that allows you to move the numbers around in addition and multiplication.
 
For example:
(addition) 1 + 2 = 2 + 1
(multiplication) 3 x 4 = 4 x 3

This property cannot be used in division or subtraction
7 0
3 years ago
Solve in fraction form.
inysia [295]

Answer:

Hey there!

Angela will have 7+2, or 9 cups of rice.

Let me know if this helps :)

4 0
4 years ago
Read 2 more answers
Please help it's due in a few minutes ASAP
wariber [46]

Answer:

110cm square

Step-by-step explanation:

Area of trapezium(regardless whatever trapezium)=

1/2 (a+b)(height)=1/2 (9+13)(10)=110cm square

8 0
3 years ago
5470
nadya68 [22]

Answer:  1144

Step-by-step explanation:

Given: Machine A makes 7 parts every 10 minutes.

i.e. it makes \dfrac{7}{10} parts in 1 minute.

Machine B makes 16 parts every 15 minutes.

i.e. it makes \dfrac{16}{15} parts in 1 minute.

On Monday,

machine A makes parts for 12 hours(720 minutes).    [1 hour = 60  minutes, 12 hours = 12 x 6 = 720 minutes]

i.e. Total parts made = \dfrac{7}{10}\times720

i.e. Total parts made = 504

machine B makes parts for 10 hours(=60x 10=600 minutes)

i.e. Total parts made = \dfrac{16}{15}\times600

i.e. Total parts made = 640

Total parts made by both machines = 504+640 =1144

Hence, the total number of parts made by the two machines on Monday=1144.

7 0
3 years ago
A boat travel 312 miles each way downstream and back. The trip downstream took 13 hours. the trip back took 26 hours. What is th
zaharov [31]
Remember that Speed= \frac{distance}{time}. Since the distance of the complete trip is 312 miles, the distance of each way is \frac{312}{2} =156 miles. 
Let  S _{b} be the speed of the boat in still water and S_{c} the speed of the current.

Now, for the downstream trip the boat is traveling with the current, so:
S_{b} +S_{c} = \frac{156}{13}
S_{b} +S_{c} =12 this will be our equation (1)

For the trip back the boat is traveling against the current, so:
S _{b} -S_{c} = \frac{156}{26}
S_{b} -S_{c} =6 this will be our equation (2)
 
Next, lets add equation (1) and equation (2) to get rid of S _{c}:
\left \{ {{S_{b}+S_{c}  =12} \atop {+(S_{b}-S_{c}  =6})} \right.
2S_{b} =18
S _{b} = \frac{18}{2}
S _{b} =9

Finally, now that we know the speed of the boat in still water, lets replace that value in our equation (1) to find the speed of the current:
9+S_{c} =12
S_{c} =12-9
S_{c} =3

We can conclude that the speed of the boath in still water is 9\frac{mi}{h}, and the current of the stream is 3\frac{mi}{h}.


7 0
4 years ago
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