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Svetlanka [38]
2 years ago
5

Can anyone please help me with this?

Mathematics
1 answer:
marin [14]2 years ago
4 0

Answer:

I believe that It would be b

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Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
21.
jasenka [17]

Answer:

b = y intercept

Step-by-step explanation:

y = mx +b

This is the slope intercept form of a line

The m is the slope and the b is the y intercept

8 0
3 years ago
Cheryl plans to bake cookies tomorrow and needs to purchase chocolate chips and pecans for no more than $25 total. Chocolate chi
boyakko [2]

The inequality that correctly represents this scenario is given as follows:

2x + 5y \leq 25

The graph is given at the end of the question.

<h3>What is a system of inequalities?</h3>

A system of inequalities is when two or more variables are related, and inequalities are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: number of chocolate chips purchased.
  • Variable y: number of pecans sold.

Chocolate chips are $2 per pound and pecans are $5 per pound. She wants to spend at most $25, hence:

2x + 5y \leq 25

More can be learned about a system of inequalities at brainly.com/question/3656398

#SPJ1

6 0
2 years ago
A car goes 400 miles on 10 gallons of
Olenka [21]

Answer:

A. 1200

Step-by-step explanation:

Since 10 times 3 is 30, then 400 times 3 is 1200. Hope I helped!

4 0
3 years ago
In a standard deck of cards there are 13 spades, 13 clubs, 13 hearts, and 13 diamonds. The spades and the clubs are black and th
Usimov [2.4K]
A 1/8.
hope this helps
4 0
3 years ago
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