Hey!!!
Answer is....
diagonals of square bisect each other at right angles.
let diagonal be 2x
Using Pythagoras in a triangle enclosed by a side and 2 half diagonals...




side of a diagonal=2 sqrt50

cm......
HOPE IT HELPS YOU '_'
To check which ordered pair (point) is in the solution set of the system of given linear inequalities y>x, y<x+1; we just need to plug given points into both inequalities and check if that point satisfies both inequalities or not. If any point satisfies both inequalities then that point will be in solution.
I will show you calculation for (5,-2)
plug into y>x
-2>5
which is clearly false.
plug into y<x+1
-2<5+1
or -2<6
which is also false.
hence (5,-2) is not in the solution.
Same way if you test all the given points then you will find that none of the given points are satisfying both inequalities.
Hence answer will be "No Solution from given choices".
Answer:
D.) 1 3/5
Step-by-step explanation:
You need 1/5 cups of flour 8 times so you need to multiply 1/5 by 8.
1/5 × 8 = 8/5
Then simplify.
8/5 = 5/5 + 3/5 = 1 3/5
Let 11x + 15y + 23 = 0 be equation (1)
And 7x - 2y - 20 = 0 be equation (2)
Multiply equation (1) by 2:
22x + 30y + 46 = 0
Multiply equation (2) by 15:
105x - 30y - 300 = 0
Add equations (1) and (2):
22x + 105x + 30y - 30y + 46 - 300 = 0
127x - 254 = 0
127x = 254
x = 254/127
[x = 2]
Substitute x = 2 in equation (1) to find y:
11(2) + 15y + 23 = 0
22 + 15y + 23 = 0
15y + 45 = 0
15y = -45
y = -45/15
y = -3
Therefore, x = 2 and y = -3.