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3 years ago

In the figure to the right, if AC=12 and BC=9, what’s the radius?

Mathematics

2 answers:

irinina [24]3 years ago

7 0

Answer:

x x 7.937 units

Step-by-step explanation:

hope this helped

Lynna [10]3 years ago

3 0

Answer:

it aproximatley 7.937 rounded to the nearest tenth its 7.9

Step-by-step explanation:

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**HELP ME ASAP! THANKS** What is the area of the triangle?

yarga [219]

54 because the formula for the area of triangle is 1/2bh so you just substitute the b and h for 18 and 6

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3 years ago

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a class has 20 trays of paint each trays has 6 colors 1 of the color is red what fraction of the colors in the 20 trays is red

Molodets [167]

Answer: it is 1/6

You can solve by saying, 1 out of 6 in each tray is red, so my fraction should be 1/6.

It doesn't matter the amount of trays because the pattern is always the same.

But if you want to check it out you can do it in this way.

You know there is 1 red color per tray, if there are 20 then you'd have 20 of them, in each tray there are 6 colors so the total is 120.

Now you solve it if there are 20 red colors out of 120 them the answer is 20/120, thus you get 1/6

Step-by-step explanation:

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3 years ago

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[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6

viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

Height (in inches) of a 25 year old man is a normal random variable with mean $g=71$ and variance $o^{2} =6.25$ .

To find: (a) What percentage of 25 year old men are 6 feet, 2 inches tall

(b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X> $74in$ ]

P[X>74] = P[ $\frac{X-g}{o}$ > $\frac{74-71}{2.5}$ ]

= P[Z > 1.2]

= 1 - P[Z ≤ 1.2]

= 1 - Ф (1.2)

= 1 - 0.8849

= 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, $6ft$ $5in$ - X, $6ft$ ]

P[X > $6ft$ $5in$ I X > $6ft$ ] = P[X > 77 I X > 72]

= $\frac{P[X > 77]}{P[ X > 72]}$

= $\frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}] }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }$

= $\frac{P[Z >2.4]}{P[Z>0.4]}$

= $\frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }$

= $\frac{1-0.9918}{1-0.6554}$

= $\frac{0.0082}{0.3446}$

= 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

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Natasha_Volkova [10]

Answer:

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Step-by-step explanation:

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Circumference of a semi-circle with diameter 30

PolarNik [594]

0.5 * 3.14 * 30 = 47.1

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3 years ago