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3 years ago

What is the answer to four thirds divides by five thirds?

1 answer:

3 0

Copy Dot Flip.
so Copy the first fraction 4/3
write a Dot • or the multiplication, so 4/3 ×
Flip the last fraction 3/5
So...
4/3 × 3/5 = 12/15 = 4/5

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PLEASE HELP I GIVE THANKS

soldier1979 [14.2K]

Well for 3. you use the Pythagorean theorem to say that 28^2 - 18^2= x^2 so 21.4 and for 4. the Pythagorean theorem says a^2 + b^2 = c^2 with c being the hypotenuse of any right triangle so the sums of the two smaller squares make the sum of the larger square making the answer b

8 0

3 years ago

What is the GCF for: 3x^3 -4x^2

serg [7]

3x^3 - 4x^2
x^2(3x - 4)

5 0

2 years ago

I will give BRAINLIEST to whoever is correct.

Shtirlitz [24]

The answer would be ab+ac

4 0

3 years ago

The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it

brilliants [131]

Answer:

(a) 11.25 and 1.68

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

$P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....$

where, n = number of trials (samples) taken = 15

r = number of success

p = probability of success which in our question is % of cases in

which customer problems are resolved on the same day, i.e.;75%

So, here X ~ $Binom(n=15,p=0.75)$

(a) Expected number of problems to be resolved today = E(X)

E(X) = $\mu$ = n * p = 15 * 0.75 = 11.25

Standard deviation = $\sigma$ = $\sqrt{n*p*(1-p)}$ = $\sqrt{15*0.75*(1-0.75)}$ = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

P(X = 10) = $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}$

= $3003*0.75^{10} *0.25^{5}$ = 0.1651

= $\binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}$

= $3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4}$ = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)

= $\binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}$

= $1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}$

= 0.6865

3 0

3 years ago

)

brilliants [131]

Answer:

Step-by-step explanation:

^^^^^^^^^ (please give me brainliest)

8 0

2 years ago