Answer:
y - 4 = 4 (x + 3)
Step-by-step explanation:
Point-slope form is y - y1 = m (x - x1)
y1 is 4, m is 4, and x1 is -3
When you plug them in, you get: y - 4 = 4 (x + 3)
Note: (x - -3) becomes (x + 3)
I hope this helps!!
<span>Simplifying
10 + -3(3x + -40) = -9x
Reorder the terms:
10 + -3(-40 + 3x) = -9x
10 + (-40 * -3 + 3x * -3) = -9x
10 + (120 + -9x) = -9x
Combine like terms: 10 + 120 = 130
130 + -9x = -9x
Add '9x' to each side of the equation.
130 + -9x + 9x = -9x + 9x
Combine like terms: -9x + 9x = 0
130 + 0 = -9x + 9x
130 = -9x + 9x
Combine like terms: -9x + 9x = 0
130 = 0
Solving
130 = 0
Couldn't find a variable to solve for.
This equation is invalid, the left and right sides are not equal, therefore there is no solution.</span>
Answer:
c₁ = 1/2 cos⁻¹ (2/π) = 0.44
c₂ = -1/2 cos⁻¹ (2/π) = -0.44
Step-by-step explanation:
the average value of f(x)=2 cos(2x) on ( − π/ 4 , π/ 4 ) is
av f(x) =∫[2*cos(2x)] dx /(∫dx) between limits of integration − π/ 4 and π/ 4
thus
av f(x) =∫[cos(2x)] dx /(∫dx) = [sin(2 * π/ 4 ) - sin(2 *(- π/ 4 )] /[ π/ 4 - (-π/ 4)]
= 2*sin (π/2) /(π/2) = 4/π
then the average value of f(x) is 4/π . Thus the values of c such that f(c)= av f(x) are
4/π = 2 cos(2c)
2/π = cos(2c)
c = 1/2 cos⁻¹ (2/π) = 0.44
c= 0.44
since the cosine function is symmetrical with respect to the y axis then also c= -0.44 satisfy the equation
thus
c₁ = 1/2 cos⁻¹ (2/π) = 0.44
c₂ = -1/2 cos⁻¹ (2/π) = -0.44
