HELP ME IMMEDIATELY WITH THIS PROBLEM PLEASE

Mathematics

2 answers:

Anna71 [15]3 years ago

7 0

Answer:

x= 7, -1

Step-by-step explanation:

took the test :)

Pachacha [2.7K]3 years ago

7 0

Answer:

$x=3 -\sqrt{2}\\x=3 + \sqrt{2}$

Step-by-step explanation:

$x=\frac{\sqrt{} 36-28}{2} \\x=\frac{6+-\sqrt{8} }{2} \\x=\frac{6+-2\sqrt{2} }{2} \\$

Then you simplify both the negative and the positive expressions

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bear in mind that tangent is sine/cosine or y/x

for the tangent to be negative, the signs of "y" and "x" must differ, and that happens only on the II and IV quadrants

and for the tangent to be positive, the signs must be same, and that's only on I and III quadrants.

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Step-by-step explanation:

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