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3 years ago

Help me plz:3 tahnk you!!

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

6 0

Answer:

1. (1, -4) => G

2. (-4, 1) => A

3. (0, -2) => H

4. (3, 5) => D

5. (2, 0) => F

Step-by-step explanation:

1. (1, -4) => when x = 1, y = -4 at point G

2. (-4, 1) => when x = -4, y = 1 at point A

3. (0, -2) => when x = 0, y = -2 at point H

4. (3, 5) => when x = 3, y = 5 at point D

5. (2, 0) => when x = 2, y = 0 at point F

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Answer:

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3 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

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Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

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Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

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$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

Step-by-step explanation:

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2 years ago