3.00/0.15 = 20
You can buy 20 pens
![\bold{\huge{\green{\underline{Solution}}}}](https://tex.z-dn.net/?f=%5Cbold%7B%5Chuge%7B%5Cgreen%7B%5Cunderline%7BSolution%7D%7D%7D%7D)
- <u>A</u><u> </u><u>car </u><u>travels </u><u>1</u><u>0</u><u> </u><u>km </u><u>southeast </u><u>and </u><u>then </u><u>1</u><u>5</u><u> </u><u>km </u><u>in </u><u>a </u><u>direction </u><u>6</u><u>0</u><u>°</u><u> </u><u>north </u><u>of </u><u>east </u>
![\bold{\underline{ To\: Find }}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cunderline%7B%20To%5C%3A%20Find%20%7D%7D)
- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>magnitude </u><u>of </u><u>the </u><u>car </u><u>of </u><u>resultant </u><u>vector</u>
![\bold{\underline{ Let's \: Begin }}](https://tex.z-dn.net/?f=%5Cbold%7B%5Cunderline%7B%20Let%27s%20%5C%3A%20Begin%20%7D%7D)
Here,
- In South east, car travels = 10km
- In North of east, it travels = 15km
- Angle between south east and north east is 60°
<u>Therefore</u><u>, </u>
According to parallelogram law of resultant vector
<u>If </u><u>two </u><u>vectors </u><u>are </u><u>represented </u><u>by </u><u>two </u><u>adjacent </u><u>sides </u><u>of </u><u>a </u><u>parallelogram </u><u>drawn </u><u>from </u><u>a </u><u>point </u><u> </u><u>,</u><u> </u><u>the </u><u>their </u><u>resultant </u><u>is </u><u>equal </u><u>to </u><u>the </u><u>diagonal </u><u>of </u><u>the </u><u>parallelogram</u><u>. </u>
<u>That </u><u>is</u><u>, </u>
![\sf{ R = AC² = A² + B²}](https://tex.z-dn.net/?f=%5Csf%7B%20R%20%3D%20AC%C2%B2%20%3D%20A%C2%B2%20%2B%20B%C2%B2%7D)
<u>But</u><u>, </u><u> </u><u>we </u><u>have </u><u>to </u><u>calculate </u><u>the </u><u>magnitude </u><u>of </u><u>the </u><u>resultant </u><u>vector </u>
![\sf{ | R |= √A² + B² + 2ABCosΦ }](https://tex.z-dn.net/?f=%5Csf%7B%20%7C%20R%20%7C%3D%20%E2%88%9AA%C2%B2%20%2B%20B%C2%B2%20%2B%202ABCos%CE%A6%20%7D)
<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>
![\sf{ | R |=√ (10)² + (15)² + 2× 10 × 15 × cos 60° }](https://tex.z-dn.net/?f=%5Csf%7B%20%7C%20R%20%7C%3D%E2%88%9A%20%2810%29%C2%B2%20%2B%20%2815%29%C2%B2%20%2B%202%C3%97%2010%20%C3%97%2015%20%C3%97%20cos%2060%C2%B0%20%7D)
![\sf{ | R | =√ 100 + 225 + 20 × 15 × 1/2}](https://tex.z-dn.net/?f=%5Csf%7B%20%7C%20R%20%7C%20%3D%E2%88%9A%20100%20%2B%20225%20%2B%2020%20%C3%97%2015%20%C3%97%201%2F2%7D)
![\sf{ | R | = √100 + 225 + 10 × 15 }](https://tex.z-dn.net/?f=%5Csf%7B%20%7C%20R%20%7C%20%3D%20%E2%88%9A100%20%2B%20225%20%2B%2010%20%C3%97%2015%20%20%7D)
![\sf{ | R | = √335 + 150 }](https://tex.z-dn.net/?f=%5Csf%7B%20%7C%20R%20%7C%20%3D%20%E2%88%9A335%20%2B%20150%20%20%7D)
![\sf{ | R | = √485 }](https://tex.z-dn.net/?f=%5Csf%7B%20%7C%20R%20%7C%20%3D%20%20%E2%88%9A485%20%7D)
![\sf{\red{ | R | = 22.02 \: km}}](https://tex.z-dn.net/?f=%5Csf%7B%5Cred%7B%20%7C%20R%20%7C%20%3D%2022.02%20%5C%3A%20km%7D%7D)
Hence, The magnitude of the car resultant vector is 22.02 km.
Answer:
Proved
Step-by-step explanation:
Figure two triangles which are congruent to each other has been attached
Proof :
1)BC= CD ( given )
2) AC= CE ( Given)
3) ∠ACB= ∠ECD ( vertically opposite to each other)
therefore, ΔABC≅ΔDCE ( By SSA postulate)
Now, CF and CG be medians on the sides Ab and DE of the Δ's ABC and DCE respectively
⇒CF= CG because of CPCTC that is corresponding parts of congruent triangles are congruent.
Therefore, congruent triangles have congruent corresponding medians.
I believe your answer is 7:40
There are 30 adults. Because if there are only three-tenths of adult visitors, you're finding 30% of 100 adult visitors. There are 30 Adults.