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seraphim [82]
3 years ago
8

Help me out. Can you help me out, please? worth 10 points good bargain.

Mathematics
1 answer:
zhuklara [117]3 years ago
6 0
- 14/11 is an irrational number. It cannot be a natural, integer, or rational number because it is not a whole number.

Your answer is: B) Irrational number 

Have an amazing day and stay hopeful!

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What are the domain and range of the exponential function below? <br><br> <img src="https://tex.z-dn.net/?f=F%28x%29%20%3D%205%5
faust18 [17]

Answer:

B

Step-by-step explanation:

The domain is the set of x values for which the function is defined.

The range is the set of y values for which the function is defined.

Attached is the graph of the exponential function.

It is the basic graph of exponential function of y = 5^x which is shifted 6 units above (because of +6 at the end).

<em><u>Looking at the graph, the domain is the set of all x values.</u></em>

<em><u>The range is anything above 6.</u></em>

Correct answer is B.

3 0
3 years ago
(02.04 MC)
borishaifa [10]

Answer:

umm idk let me get back to you

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
Midpoint.<br> (3,3), (-1,1)
Scilla [17]

Answer:

1,2

Step-by-step explanation:

3+-1=2

2/2=1  

3+1=4

4/2=2

7 0
3 years ago
How can i solve the following <br> 4x-3=2x+7
yan [13]

Answer:

x = 5

Step-by-step explanation:

Note the equal sign, what you do to one side, you do to the other. Isolate the variable, x.

Add 3 and subtract 2x from both sides of the equation:

4x (-2x) - 3 (+3) = 2x (-2x) + 7 (+3)

4x - 2x = 7 + 3

2x = 10

Next, isolate the x by dividing 2 from both sides of the equation:

(2x)/2 = (10)/2

x = 10/2

x = 5

5 is your answer for x.

~

6 0
3 years ago
Read 2 more answers
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