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3 years ago

WHICH OF THE FOLLOWING REPRESENTS A NON LINEAR EQUATION

Mathematics

1 answer:

sertanlavr [38]3 years ago

3 0

Answer:

y = 3/x

Step-by-step explanation:

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What is the value of the 4's of 305,444

matrenka [14]

All of 4's value is hundreds, tens, and ones.

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4 years ago

The equation represents an ellipse. which point is the center of the ellipse? (−9, 5) (−5, 9) (5, −9) (9, −5)

Igoryamba

The point which is the center of the ellipse whose equation is; (y+5)²/121+(x-9)²/49=1 s in the task content is; (-5, 9).

<h3>Which point represents the center of the ellipse whose equation is given as; (y+5)²/121+(x-9)²/49=1?</h3>

It follows from convention that the equation of an ellipse usually takes the form;

(y-h)²/a²+(x-k)²/b²=1 in which case, the center of the ellipse is given by the point; (h, k).

On this note, By comparison of the actual equation and the standard equation, it follows that;

+5 = -h and consequently, h = -5,

-9 = -k and consequently, k = 9.

Ultimately, the point which is the center of the

ellipse is; (-5, 9).

Remark: The equation of the ellipse which is missing in the task content is; (y+5)²/121+(x-9)²/49=1

Read more on center of an ellipse;

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2 years ago

Emily is entering a bicycle race for charity. Her mother pledges $0.30 for every 0.75 mile she bikes. If Emily bikes 24 miles, h

nexus9112 [7]

Answer:

9.60 dollas

Step-by-step explanation:

24/0.75=32

32x0.30=9.6

4 0

3 years ago

Lines a and b are perpendicular. If the slope of line a is 3, what is the slope of line b?

erma4kov [3.2K]

Answer:

$\large\boxed{D.\ -\dfrac{1}{3}}$

Step-by-step explanation:

$\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2,\ \text{then}\\\\l\ ||\ k\iff m_2=m_1\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\-------------------\\\\\text{We have the slope of given line a:}\ m_1=3.\ \text{Therefore the slope of a line b}\\\text{perpendicular to a is: }\\\\m_2=-\dfrac{1}{m_1}\to m_2=-\dfrac{1}{3}$

3 0

3 years ago

Read 2 more answers

Ashley is a 130 lb athlete who biked on a cycle ergometer at a steady state of exercise for 48 minutes. Her average VO2 was 2.72

Xelga [282]

Answer:

correct option is D. 630 kcals

Step-by-step explanation:

given data

Ashley weight = 130 lb

exercise time = 48 minutes

VO2 = 2.72 LO2/min

VCO2 = 2.24 LCO2/min

to find out

total energy expenditure

solution

first we get here respiratory exchange ratio that is

respiratory exchange ratio (RER) = $\frac{VCO2}{VO2}$ ...........1

RER = $\frac{2.24}{2.72}$

RER = 0.823

now we get here calorific value that is

calorific value = 3.815 + 1.23 × RER

calorific value = 3.815 + 1.23 × 0.823

calorific value = 4.827 kcal/L O2

so now we get energy expended that is

energy expended = VO2 × calorific value × time

energy expended = 2.72 × 4.827 × 48

energy expended = 630 kcals

so correct option is D. 630 kcals

4 0

3 years ago