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Lelu [443]
3 years ago
9

I don't understand. ​

Mathematics
2 answers:
Furkat [3]3 years ago
7 0

Answer:

<h2><em><u>symmetric</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em></h2>
Vedmedyk [2.9K]3 years ago
6 0

Answer:

the second choice took the test

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Which of the follong is the process of finding the factors of mathematical expression 2d²-8d​
zhenek [66]

Answer:

2d(d - 4)

Step-by-step explanation:

Given

2d² - 8d ← factor out the common factor of 2d from each term

= 2d(d - 4) ← in factored form

6 0
3 years ago
Please help. will give brainliest to correct answer :)
e-lub [12.9K]

Answer:

(3,-5)

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
PLEASE HELP!!
erik [133]
2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha

1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}

3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x
8 0
3 years ago
Solve |y - 2|&lt;10<br><br> {y|-8 &lt; y &lt; 12}<br> {y|-12 &lt; y &lt; 8}<br> {y|-8 &lt; y &lt; 8}
lukranit [14]
The answer is -8 < y < 12
3 0
3 years ago
A number x decreased by 3 is 5​
zysi [14]

Answer:

8

Step-by-step explanation:

x - 3 = 5

x = 5 + 3

x = 8

Therefore, the number is 8.

5 0
3 years ago
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