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makkiz [27]
3 years ago
6

If a standard 6 sided dice is rolled. (Write your answers as a decimal, rounded to the nearest hundredth.) Find: a. Probability

of rolling one die and it landing on both a prime number and a multiple of two. b.Probability of rolling one die and it landing on a 3 or a prime number. c. P(3 U Multiple of 2) = d. P(2 U Even number) =
Mathematics
1 answer:
pshichka [43]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

The possible outcomes are 1,2,3,4,5,6

P( a prime number and a multiple of two)

The only prime number that is a multiple of 2 is 2

P( a prime number and a multiple of two) = number of outcomes / total outcomes

P( a prime number and a multiple of two) = 1/6 = .17

P(3 or a prime number)

The prime numbers are 2,3,5  and 3 is included in this list so we have 3 outcomes

P( 3 or a prime number) = number of outcomes / total outcomes

P( 3 or a prime number) =3/6 =1/2= .5

P(3 U Multiple of 2)

Multiples of 2 are 2,4,6 and add 3 to the list  so there are 4 outcomes

P( 3 U Multiple of 2) = number of outcomes / total outcomes

P( 3 or a prime number) =4/6 =2/3= .67

P(2 U Even number)

even numbers are 2,4,6 and 2 is on the list  so there are 3 outcomes

P( 2 U Even number) = number of outcomes / total outcomes

P( 3 or a prime number) =3/6 =1/2= .5

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Class A has 15 pupils and class B has 29 pupils.
Vaselesa [24]

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

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An equation is an expression that shows the relationship between two or more numbers and variables.

Class A has 15 pupils and class B has 29 pupils. The mean score for class A is 55. Hence:

Mean score of A = (sum of all scores) / 15

55 =  (sum of all scores) / 15

sum of all scores in A = 825

The mean score for both classes is 76. Hence:

[(sum of all scores in A) + (sum of all scores in B)]/(total number of pupils) = mean score of both classes

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sum of all scores in B = 2519

Mean score of B = (2519) / 29 = 86.86

The mean score (rounded to 2 DP) in the Math's test for class B is 86.86.

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6 0
1 year ago
Suppose f varies directly as g, and f varies inversely as h. Find g when f = 10 and h = –12, if g = 56 when h = –2 and f = –7. R
kow [346]

Answer:

-480

Step-by-step explanation:

If f varies directly as g, and inversely as h, then we can write the variation equation:

f=\frac{kg}{h}, where k is the constant of variation.

If g=56 when h=-2 and f=-7, then we substitute these values into the formula to find the value of k.

-7=\frac{k(56)}{-2}

-7\times -2=56k

k=\frac{14}{56}=\frac{1}{4}

The equation now becomes:

f=\frac{g}{4h}

if f=10 and h=-12, then;

10=\frac{g}{-48}

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4 0
3 years ago
A rectangle has a perimeter of 60 units and one side of length 18 units. If it can be determined, what are the lengths, in units
ladessa [460]

Answer:

option B. 18,12,12

Step-by-step explanation:

perimeter= 60 units

(consider a rectangle with sides a,b,c & d in order)

a= 18 units (given)

c=18 units (since opp. sides of a rectangle are equal)

now the remaining length= 60-(18+18)

                                          = 60 - 36

                                          = 24

so the sum of the remaining sides, ie, b+d= 24

since b and d are equal (opp.sides of a rect.)

b=d=24/2=12

therefore, b=12; c=18; d=12

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