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makkiz [27]
3 years ago
6

If a standard 6 sided dice is rolled. (Write your answers as a decimal, rounded to the nearest hundredth.) Find: a. Probability

of rolling one die and it landing on both a prime number and a multiple of two. b.Probability of rolling one die and it landing on a 3 or a prime number. c. P(3 U Multiple of 2) = d. P(2 U Even number) =
Mathematics
1 answer:
pshichka [43]3 years ago
4 0

Answer:

see below

Step-by-step explanation:

The possible outcomes are 1,2,3,4,5,6

P( a prime number and a multiple of two)

The only prime number that is a multiple of 2 is 2

P( a prime number and a multiple of two) = number of outcomes / total outcomes

P( a prime number and a multiple of two) = 1/6 = .17

P(3 or a prime number)

The prime numbers are 2,3,5  and 3 is included in this list so we have 3 outcomes

P( 3 or a prime number) = number of outcomes / total outcomes

P( 3 or a prime number) =3/6 =1/2= .5

P(3 U Multiple of 2)

Multiples of 2 are 2,4,6 and add 3 to the list  so there are 4 outcomes

P( 3 U Multiple of 2) = number of outcomes / total outcomes

P( 3 or a prime number) =4/6 =2/3= .67

P(2 U Even number)

even numbers are 2,4,6 and 2 is on the list  so there are 3 outcomes

P( 2 U Even number) = number of outcomes / total outcomes

P( 3 or a prime number) =3/6 =1/2= .5

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